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3 years ago

- What is the range of the following set of points: {(3, 4), (7, - 2), (11, – 8)}?

Mathematics

1 answer:

konstantin123 [22]3 years ago

3 0

Answer:

B) {-8,-2,3,4,7,11}

Step-by-step explanation:

range is y

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A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data greater tha

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2 years ago

Can you all please help me with problems 6 through 10? Please don’t use for points I’m extremely stressed and need help

patriot [66]

Answer:

See below.

Step-by-step explanation:

6.) (5)/6 ≤ 1 (Yes)

7.) 1.4(11) > 16

15.4 > 16 (No)

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2 years ago

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2 years ago

In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the

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Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

$P(A) = 0.01 , P(B) = 0.02$

We also know the probability that the memory and the hard drive fail simultaneously given by:

$P(A \cap B) = 0.0014$

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

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2 years ago