All categories

2 years ago

Help!! What is the measure of QS?

Mathematics

2 answers:

Viefleur [7K]2 years ago

7 0

Let the center of the given circle is O .

And central angle is double of the angle subtended by the arc.

So central angle is twice of 84 degree.

And twice of 84 is 168 degree.

So the central angle is of measurement 168 degree.

And central angle is the measurement of the arc , therefore measurement of arc QS is 168 degree.

Yanka [14]2 years ago

7 0

Answer:

168

Step-by-step explanation:

took assignment

You might be interested in

Val rented a bicycle while she was on vacation she paid a flat rental fee of $55.00 plus $8.50 each day the total cost was $123

artcher [175]

Answer:

55+8.5x=123

Step-by-step explanation:

The 55 represents the flat fee, the 8.5 represents the daily charge, x represents the number of days she rented it for, and 123 is the total amount

3 0

3 years ago

Read 2 more answers

I need help to evaluate the function for the given value of x for y=2×5x; x=2

mars1129 [50]

Answer:

y= 20

Step-by-step explanation:

y=2*5x

Let x =2

y = 2*5 (2)

y = 10*2

y= 20

8 0

2 years ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

2 years ago

Which graph could be used to show the situation described?

trasher [3.6K]

It would be the top right
because they are increasing by intervals of 4 each time. it can’t be the others because top left those are increasing by 5, bottom left decreasing by 4, and bottom right decreasing by .5.

4 0

3 years ago

Read 2 more answers

A box is contructed out of two different types of metal. the metal for the top and bottom, which are both square, costs $5 per s

patriot [66]

Total cost, C = 8x^2 + 12xz
volume, V = (x^2)*z = 10
C = 8x^2 + 12x*10/x^2
= 8x^2 + 120/x
dC/dx = 16x - 120/x^2 = 0
16x = 120/x^2
x^3 = 120/16
x = 1.957 ft

d^2C/dx^2 = 16 +240/x^3 = +ve for x = 1.957
so, C is minimum when
x = 1.957 ft z = 2.61 ft

Length of the base x is 1.957 ft and height of side z is 2.61 ft

3 0

3 years ago