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mario62 [17]
3 years ago
9

Can someone please help me with these two?? (With a clear answer please)

Mathematics
1 answer:
suter [353]3 years ago
4 0
Try this solution:
rule: the volume of any cylinder can be calculated with formula: V=πr²h, where r - the radius of the base, h - height  of the cylinder.
Using the formula written above:
5. V=π*25*6=150*3.1415≈471.2389≈471.2 cm³;
6. V=π*64*4=256*3.1415≈804.2477≈804.3 cm³
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Answer:

$15

Step-by-step explanation:

60x75%

60x0.75

45

60-45=15

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What is the value of x to the nearest tenth
marishachu [46]

You will have to use trig to solve this:

The side you have is adjacent to the known angle

The side you are looking for is opposite the known angle

^^^This means you need to use tan:

tan(24) = \frac{x}{12}

.445222 = \frac{x}{12}

^^^input tan(24) into calculator, then multiply 12 to both sides to isolate and solve for x

5.3 ≈ x

Hope this helped!

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What is the measure of ABD
Paladinen [302]

Answer:

Where is the question?

Step-by-step explanation:

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6 0
3 years ago
Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x
Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

(x-h)^2+(y-k)^2=r^2

Where the point (h,k)  is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121

Add 10x to both sides:

x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121

Make two groups for variable "x" and variable "y":

(x^2+10x)+(y^2-20y)=-121

Complete the square:

Add (\frac{10}{2})^2=5^2 inside the parentheses of "x".

Add  (\frac{20}{2})^2=10^2  inside the parentheses of "y".

Add 5^2 and 10^2 to the right side of the equation.

Then:

(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4

Rewriting, you get that the equation of the circle in center-radius form is:

 (x+5)^2+(y-10)^2=2^2

You can observe that the radius of the circle is:

r=2

And the center is:

(h,k)=(-5,10)

6 0
3 years ago
Read 2 more answers
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