Ask question

Ask question

All categories

3 years ago

9

Can someone please help me with these two?? (With a clear answer please)

1 answer:

suter [353]3 years ago

4 0

Try this solution:
rule: the volume of any cylinder can be calculated with formula: V=πr²h, where r - the radius of the base, h - height of the cylinder.
Using the formula written above:
5. V=π*25*6=150*3.1415≈471.2389≈471.2 cm³;
6. V=π*64*4=256*3.1415≈804.2477≈804.3 cm³

You might be interested in

RUDIKE [14]

Answer:

$15

Step-by-step explanation:

60x75%

60x0.75

45

60-45=15

5 0

3 years ago

What is the value of x to the nearest tenth

marishachu [46]

You will have to use trig to solve this:

The side you have is adjacent to the known angle

The side you are looking for is opposite the known angle

^^^This means you need to use tan:

tan(24) = $\frac{x}{12}$

.445222 = $\frac{x}{12}$

^^^input tan(24) into calculator, then multiply 12 to both sides to isolate and solve for x

5.3 ≈ x

Hope this helped!

4 0

3 years ago

What is the measure of ABD

Paladinen [302]

Answer:

Where is the question?

Step-by-step explanation:

7 0

3 years ago

earnstyle [38]

12 times 2 is 24, and 24 times 2 is 48, so there was 48 cookies

6 0

3 years ago

Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x

Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

$(x-h)^2+(y-k)^2=r^2$

Where the point (h,k) is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

$x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121$

Add 10x to both sides:

$x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121$

Make two groups for variable "x" and variable "y":

$(x^2+10x)+(y^2-20y)=-121$

Complete the square:

Add $(\frac{10}{2})^2=5^2$ inside the parentheses of "x".

Add $(\frac{20}{2})^2=10^2$ inside the parentheses of "y".

Add $5^2$ and $10^2$ to the right side of the equation.

Then:

$(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4$

Rewriting, you get that the equation of the circle in center-radius form is:

$(x+5)^2+(y-10)^2=2^2$

You can observe that the radius of the circle is:

$r=2$

And the center is:

$(h,k)=(-5,10)$

6 0

3 years ago

Read 2 more answers