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mario62 [17]
3 years ago
9

Can someone please help me with these two?? (With a clear answer please)

Mathematics
1 answer:
suter [353]3 years ago
4 0
Try this solution:
rule: the volume of any cylinder can be calculated with formula: V=πr²h, where r - the radius of the base, h - height  of the cylinder.
Using the formula written above:
5. V=π*25*6=150*3.1415≈471.2389≈471.2 cm³;
6. V=π*64*4=256*3.1415≈804.2477≈804.3 cm³
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andrew11 [14]
Ummm not to freak you out but what’s that in the background?
3 0
3 years ago
First use the digits in the box to create the largest possible number. Then use the same digits to create the smallest possible
nordsb [41]

Answer:

What are the digits in the box?

Step-by-step explanation:

3 0
3 years ago
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

6 0
3 years ago
There are approximately 7.7 billion humans on Earth. If the virus spreads beyond the 200-person town, how long will it be until
eimsori [14]

Answer:

25.2 weeks until everyone on the planet is infected

Step-by-step explanation:

The number of infected people after t weeks has the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the initial number of infected people and r is the growth rate, as a decimal.

The number of infected people doubles every week

This means that P(1) = 2P(0)

So

P(t) = P(0)(1+r)^{t}

2P(0) = P(0)(1+r)

1 + r = 2

r = 1

So

P(t) = P(0)*(2)^{t}

200-person town

This means that P(0) = 200

So

P(t) = P(0)*(2)^{t}

P(t) = 200*(2)^{t}

How long will it be until everyone on the planet is infected?

This is t for which P(t) = 7700000000[/tex]

So

P(t) = 200*(2)^{t}

7700000000 = 200*(2)^{t}

2^{t} = \frac{7700000000}{200}

\log{2^{t}} = \log{\frac{7700000000}{200}}

t\log{2} = \log{\frac{7700000000}{200}}

t = \frac{\log{\frac{7700000000}{200}}}{\log{2}}

t = 25.2

25.2 weeks until everyone on the planet is infected

4 0
3 years ago
I didn't get them all right. Can someone help please?
Tomtit [17]

Answer:

\sqrt{2.56}

6.828...

1.75

14/3

-40

Step-by-step explanation:

A rational number is any number that can be expressed as a ratio.

7 0
3 years ago
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