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coldgirl [10]
3 years ago
12

What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15?

Enter your answer in the box
Mathematics
2 answers:
Inga [223]3 years ago
7 0

Answer:

Step-by-step explanation:

Use the point-slope formula by the line

y - y_1 = m(x - x_1)      when  x_1 =8   and  y_1 = -2    m :  is the slope (same slope for the line whose equation is 3x + 4y = 15 because are  parallel)

calculate : m

3x + 4y = 15

4y = -3x +15

y = (-3/4)x +15/4     so   m = -3/4

an equation is : y +2 =(-3/4)(x-8)

Anvisha [2.4K]3 years ago
7 0

Answer:

The required equation of line is 3x+4y=16

Step-by-step explanation:

Given : A line that passes through the point (8, -2) and is parallel to the line whose equation is 3x + 4y = 15

To find : What is the equation of a line ?

Solution :

We know that,

When two lines are parallel then their slopes are equal.

The equation of line is 3x + 4y = 15

Convert into slope form y=mx+c,

4y =-3x+ 15

y=\frac{-3x+15}{4}

y=-\frac{3}{4}x+\frac{15}{4}

The slope of the line is m=-\frac{3}{4}

The line passes through (8,-2).

The general point slope form is (y-y_1)=m(x-x_1)

i.e. (y-(-2))=-\frac{3}{4}(x-8)

y+2=-\frac{3}{4}(x-8)

4y+8=-3x+24

3x+4y=16

Therefore, the required equation of line is 3x+4y=16

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5 0
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Vera_Pavlovna [14]

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