As this rectangle has it's sides parallel to x axis and y axis
it is easy to find the length of it's sides by counting the number of blocks on each sides.
Let us first find co ordinates of all four points
we would calculate them left and right and up down direction from the origian ( the cross point of x and y axis )
A : it is 2 unit left 2 unit up ( -2 , +2 )
B is 5 unit right 2 unit up ( +5 ,+2)
C is 5 unit right 2 unit down ( +5,-2)
D is 2 unit left 2 unit down ( -2,-2)
Let us now find the distance AB : A is 2 unit left B is 5 unit right so length AB= 2+5 = 7
Let us now find distance AD : A is 2 unit up and D is 2 unit down
so length AD= 2+2= 4
Answer should be 7 x 4 units
The answer is 0.3 cause when you subtract all of it you can get it
We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Answer:36
Step-by-step explanation:
2=x/4-7
9=x/4
36=x
Answer:
option B. MB/AM=NC/AN
Step-by-step explanation:
we know that
The <u><em>Triangle Proportionality Theorem</em></u> states that if a line is parallel to one side of a triangle and it intersects the other two sides, then it divides those sides proportionally
In this problem
MN is parallel to BC
MN intersect AC and divide into AN and NC
MN intersect AB and divide into AM and MB
so
Applying the Triangle Proportionality Theorem

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