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aev [14]
3 years ago
13

Nick has to build a brick wall. Each row of the wall requires 62 bricks. There are 10 rows in the wall. How many bricks will Nic

k require to build the wall?
A. 102 × 6
B. 106
C. 610
D. 10 × 62
Mathematics
1 answer:
Alja [10]3 years ago
6 0
We know that each row would require 62 bricks, and considering that the wall will have multiple rows, we will be multiplying 62 by the number of rows. Since the wall has 10 rows, Nick has to use the 62 bricks 10 times (since 1 row requires 62 bricks, he would have to build that 1 row 10 times.)

If we think about the operation of multiplication, we can write “62 ten times” as 62 x 10 (or, when calculated, 620 bricks).
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What is the product of (−4)⋅(−4)⋅(−4)⋅y⋅y using exponents
Amiraneli [1.4K]

Answer:

(-4)^{3*y^{2}

This should be right.

3 0
3 years ago
How do you work this problem? 5 - 2x = 0
ss7ja [257]

Answer:

x = 5/2

Step-by-step explanation:

Isolate x by adding 2x to both sides, obtaining:  5 - 2x + 2x = 2x.  Then 5 = 2x, and dividing both sides by 2 results in x = 5/2.


6 0
3 years ago
What is true about the solution of x^2/2x-6=9/6x-18?
pogonyaev

Answer:

  • x = ±√3, and they are actual solutions
  • x = 3, but it is an extraneous solution

Step-by-step explanation:

The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...

... x^2(6x -18) = (2x -6)(9)

... 6x^2(x -3) -18(x -3) = 0

...6(x -3)(x^2 -3) = 0

... x = 3, x = ±√3

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Alternatively, you can subtract the right side of the equation and collect terms to get ...

... x^2/(2(x -3)) - 9/(6(x -3)) = 0

... (1/2)(x^2 -3)/(x -3) = 0

Here, the solution will be values of x that make the numerator zero:

... x = ±√3

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So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.

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<em>Comment on the graph</em>

For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.

7 0
3 years ago
Read 2 more answers
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
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luda_lava [24]

Find the volume of the candle using the formula for volume of a cylinder:

V = PI x r^2 x h = 3.14 x 3.4^2 x 6 = 217.79 cubic cm. Round to 217.8

Find the volume of the block: V = l x w x h = 15 x 12 x 18 = 3,240 cubic cm.

Now divide the volume of the block by the volume of a candle:

3240 / 217.8 = 14.88

Round to the nearest tenth = 14.9 candles.

3 0
3 years ago
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