Answer:
A)less
Explanation:
This is because obviously if it's less metallic then it won't have similar traits to metals as well, there's less metal.
In the reaction of water, 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.
<h3>What is reducing agent?</h3>
A reducing agent is a type of chemical that "donates" an electron to another atom that needs an electron. This type of reaction in which loss of electron occurs is called reduction reaction.
So we can conclude that 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.
Learn more about reduction here: brainly.com/question/3457976
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Stoichiometry is “quantitative relationship” among the “reactants” and the “products” in a “chemical reaction”.
<u>Explanation</u>:
In stoichiometry “stoicheion” means element and “metron” means measure in Greek. The stoichiometric calculation depends upon “stoichiometric coefficients” in a “chemical equation” which can be explained as the “number of moles” of each substance (reactants or products). Stoichiometric calculation is done as follows:
For example reaction between nitrogen and hydrogen to form ammonia as

Here stoichiometric coefficients show that “one molecule of nitrogen” reacts with “three molecules of hydrogen” to form “two molecules of ammonia”. Multiplying Avogadro number
to no of molecules in equation:


Taking molar masses into consideration:



Hence balanced equation gives stoichiometric coefficients which gives proportion by moles.
Answer:
D) 1 iron(II), 2 chloride
Explanation:
Iron II chloride is the compound; FeCl2. It is formed as follows, ionically;
Fe^2+(aq) + 2Cl^-(aq) -----> FeCl2
The formation of one mole of FeCl2 involves the reaction one mole of iron and two moles of chloride ions. This means that in FeCl2, the ratio of iron to chlorine is 1:2 as seen above.
Therefore there is one iron II ion and two chloride ions in each mole of iron II chloride, hence the answer.
Answer:
3.75 moles
Explanation:
The chemical equation is 2CH₃OH + 3O₂ -> 2CO₂ + 4H₂O
2 moles of CH₃OH are burned by 3 moles of O₂
For 2.5 moles of CH₃OH are burned by x moles of O₂
Let's solve for x :
2*x=2.5*3 => 2*x=7.5 => x=3.75 moles of O₂ are needed to burn 2.5 moles of CH₃OH