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statuscvo [17]
2 years ago
7

In naming the compound PCl5, the prefix used with the second element is ____________________.

Chemistry
1 answer:
Oksanka [162]2 years ago
6 0

Answer:

\boxed {\boxed {\sf Hepta}}

Explanation:

We are given the formula:

PCl_5

This is a molecular formula, because it contains nonmetals.

1. Name the first element

The first element is phosphorous (P). Since this is the first element and there is only one, we don't need a prefix.

  • Phosphorous

2. Second element

The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of <u>hepta</u>-.

  • Phosphorous heptachlorine

Add the ending of -ide.

  • Phosphorous heptachloride

The prefix used for the second element is hepta. The compound name is phosphorous heptachloride.

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A graduated cylinder was filled with 25.0 mL of water. A solid object was immersed in the cylinder, raising the water level to 3
yawa3891 [41]

Answer:

Density of the object is 8759.494 grams/L

Explanation:

As we know density of an object is mass of the object divided by its volume

Given

Volume of the object is equal to the change in volume of water with in the cylinder when the object was immersed in water.

Hence, volume of object is equal to

32.9 -25 = 7.9 mL

Mass of the object is 69.2 grams

Density

= \frac{69.2}{7.9 *10^{-3}}\\= 8759.494 grams/L

Density of the object is 8759.494 grams/L

7 0
3 years ago
Calculate the number of chlorine atoms that are present in 66.05 g of dichloromethane, ch2cl2. when you have the number, take it
Whitepunk [10]
From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of chlorine = 35.5 grams
Therefore,
molar mass of CH2Cl2 = 12 + 2(1) + 2(35.5) = 85 grams

number of moles = mass / molar mass
number of moles of CH2Cl2 = 66.05 / 85 = 0.777 moles

One mole of CH2Cl2 contains two moles of Cl and each chlorine mole has Avogadro's number of atoms in it.
Therefore,
number of chlorine atoms in 0.777 moles of CH2Cl2 can be calculated as follows:
number of atoms = 0.777 * 2 * 6.022 * 10^23 = 9.358 * 10^23 atoms

Now, we will take log base 10 for this number:
log (9.358 * 10^23) = 23.97119
5 0
3 years ago
A particular reactant decomposes with a half-life of 113 s when its initial concentration is 0.372 M. The same reactant decompos
AysviL [449]

Answer:

Rate constant =  0.0237 M-1 s-1, Order = Second order

Explanation:

In this problem, it can be observed that as the concentration decreases, the half life increases. This means the concentration of the reactant is inversely proportional to the half life.

The order of reaction that exhibit this relationship is the second order of reaction.

In the second order of reaction, the relationship between rate constant and half life is given as;

t1/2 = 1 / k[A]o

Where;

k = rate constant

[A]o = Initial concentration

k = 1 / t1/2 [A]

Uisng the following values;

k = ?

t1/2 = 113

[A]o = 0.372M

k = 1 / (113)(0.372)

k = 1 / 42.036 = 0.0237 M-1 s-1

8 0
3 years ago
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Mnenie [13.5K]

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chubhunter [2.5K]

Answer:

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Explanation:

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