Answer:
0.316 moles are produced.
Explanation:
We state the redox reaction:
4HNO₃ + Cu → Cu(NO₃)₂ + 2NO₂ + 2H₂O
We need to determine the limting reactant:
0.1 L . 14 M = 1.4 moles
10 g . 1mol/ 63.54g =0.158 mol
Cu is the limiting reactant. Let's see
4 moles of acid need 1 mol of Cu to react
1.4 moles of acid may react to (4 . 1) / 1.4 = 0.35 moles
We do not have enough Cu.
1 mol of Cu can produce 1 mol of NO₂
Then 0.158 moles will produce, 0.316 moles. (double of moles)
If we see stoichiometry, ratio is 1:2
We have that the Concentration of solution B is 2.5 times more than solution A's concentration.
<h3>UV(Ultra violent) rays</h3>
Question Parameters:
Upon UV-analysis, Solution B gave an absorbance of 1.0
Solution A gave an absorbance of 0. 4
Generally the equation for the Absorbance is mathematically given as
A = e*c*L
Therefore
For A solution
![0.4 = e*[cA]*L](https://tex.z-dn.net/?f=0.4%20%3D%20e%2A%5BcA%5D%2AL)
For B solution
![1.0 = e*[cB]*L](https://tex.z-dn.net/?f=1.0%20%3D%20e%2A%5BcB%5D%2AL)
Hence
![\frac{0.4}{ 1} = \frac{[cA]}{ cB}](https://tex.z-dn.net/?f=%5Cfrac%7B0.4%7D%7B%201%7D%20%3D%20%5Cfrac%7B%5BcA%5D%7D%7B%20cB%7D)
[cB] = 2.5 [cA]
Therefore
Concentration of solution B is 2.5 times more than solution A's concentration.
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brainly.com/question/3004869
Answer:
The density of water is about 1.0 g/mL at room temperature.
Briefly explain how the density of an aqueous solution at room temperature can be significantly less than 1.0 g/mL.
Give an example of such a solution.
Explanation:
That means 1.0mL of water weighs ---- 1.0g
If any other aqueous solution which has mass less than 1.0g will have density less than 1.0g.
For example aqueous solution of sulfuric acid has density 0.98g/mL.
That means 1mL of sulfuric acid has mass 0.98g.
Answer:
3.40 g
Explanation: don't have one :P