A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.0.25 M0.44 M0.75 M4.0 M
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The limiting reactant is iron ore, the theoretical yield of iron metal is 701.344 kg, and the theoretical yield of carbon dioxide is 413.292 kg.
<h3>Stoichiometric problem</h3>From the equation of the reaction:
The mole ratio of iron ore to carbon is 2:3.
Mole of 1000 kg of iron ore = 1000000/159.69
= 6,262 moles
Mole of 120 kg carbon = 120000/12
= 10,000 moles
Thus, it appears that the carbon is in excess while the iron ore is limited in availability.
The mole ratio of the iron ore and the iron produced is 1:2. Thus, the equivalent number of moles of iron produced will be:
6,262 x 2 = 12,524 moles
Mass of 12,524 moles of iron = 12,524 x 56
= 701,344 g or 701.344 kg
Thus, the theoretical yield of iron is 701.344 kg.
The mole ratio of the iron ore and the carbon dioxide produced is 2:3. The equivalent mole of carbon dioxide produced will be:
6,262 x 3/2 = 9,393 moles
Mass of 9,393 moles carbon dioxide = 9,393 x 44
= 413,292 or 413.292 kg
The theoretical yield of carbon dioxide is, therefore, 413.292 kg.
More on stoichiometric problems can be found here: brainly.com/question/14465605
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The relationship between the volume, temperature, and pressure of the gas can be given by Charles law. The volume of the tire is 1.1 L.
<h3>What is Charle's law?</h3>According to Charles's law, the volume is directly proportional to the temperature of the gas at a constant pressure.
Charle's law can be shown as,
Given,
Initial volume = 1.0 L
Initial temperature = 295 K
Final volume = ?
Final temperature = 325 K
Substituting values in the above equation the final volume can be calculated as:
Therefore, the final resulting volume of the tire is 1.1 L.
Learn more about Charle's law here: