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son4ous [18]
3 years ago
15

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.0.25 M0.44 M0.75 M4.0 M

Chemistry
2 answers:
notka56 [123]3 years ago
6 0

The molecular mass of H_2SO_4 is:


2·1 + 1·32 + 4·16 = 98 g/mol


The amount of solute, expressed by mol, is:


73.5\ g\ H_2SO_4\cdot \frac{1\ mol}{98\ g} = 0.75\ mol\ H_2SO_4


The molar concentration definition is: M = \frac{mol\ solute}{volume (L)\ solution}


Doing the calculations:


M = \frac{0.75\ mol}{3\ L} = \bf 0.25\ M


(If you detect any mistakes in my English report me them, please).

densk [106]3 years ago
4 0

Answer:

0.25

Moles of solute = (Liters of solution) x (molarity of solution)

Moles of solute = (Kg of solution) x (molality of solution)

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