Question

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.0.25 M0.44 M0.75 M4.0 M

Answer 1

The molecular mass of $H_2SO_4$ is:

2·1 + 1·32 + 4·16 = 98 g/mol

The amount of solute, expressed by mol, is:

$73.5\ g\ H_2SO_4\cdot \frac{1\ mol}{98\ g} = 0.75\ mol\ H_2SO_4$

The molar concentration definition is: $M = \frac{mol\ solute}{volume (L)\ solution}$

Doing the calculations:

$M = \frac{0.75\ mol}{3\ L} = \bf 0.25\ M$

(If you detect any mistakes in my English report me them, please).

Answer 2

Answer:

0.25

Moles of solute = (Liters of solution) x (molarity of solution)

Moles of solute = (Kg of solution) x (molality of solution)