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Tems11 [23]
3 years ago
7

Someone pls answer this correctly pls ! IXL Geometry area between two shapes.

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

240 square centimeters

1. Find the area of the green figure, which is 529. Then find the area of the white figure, which is 289.

2. Subtract 289 from 529.

529 - 289 = 240

Anika [276]3 years ago
3 0

Answer:

240\ cm^{2}

Step-by-step explanation:

A = 23^{2} - 17^{2} = 529 - 289 = 240\ cm^{2}

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Bonita deposited $1300 into a bank account that earned 5.75% simple interest each year. She earned $299 in interest before closi
nika2105 [10]

Bonita deposited $1300 into a bank account that earned 5.75% simple interest each year.

She earned $299 in interest before closing the account.

Principle =  $1300

Rate =  5.75%

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In the 2004 Olympics, Adam won a gold medal in the men's 500 m kayak race, with a time of 1 min and 37.9 sec. He also won the br
Sedbober [7]

Answer:

The correct answer is Adam rowed faster in the men's 500-meter kayak race.

Step-by-step explanation:

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3 0
3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
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