You gotta show the answer options so I can choose the right answer
The base of a logarithm should always be positive and can't be equal to 1, so the domain is 0 < <em>x</em> < 1 or <em>x</em> > 1.

Write both sides as powers of 1/<em>x</em> :

Recall that
, so that



Take the 5th root of both sides, recalling that 3⁵ = 243, so
![x=\sqrt[5]{\dfrac1{243}}=\boxed{\dfrac13}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B5%5D%7B%5Cdfrac1%7B243%7D%7D%3D%5Cboxed%7B%5Cdfrac13%7D)
The value of x
3x°+46°+(2x-1°)=180°(angle sum of △)
5x+45=180°
5x=180°-45
x=135÷5
x=27
x is 27
put x into angle B,we have
2(27)-1
=53
thus angleB is 53°
hope it helps c:
Answer:
3/16
Step-by-step explanation:
Answer:
5.
x + 2(x + 1) = 8 --> x = 2
y = 2 + 1 = 3
7.
3(9 + 2y) + 5y = 20 --> y = -7/11
x = 9 + 2(-7/11) = 85/11
9.
3(-1 - 2y) + 5y = -1 --> y = -2
x = -1 - 2(-2) = 3