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2 years ago

What is the y intercept of the following equation -y+x=0

Mathematics

2 answers:

Vinvika [58]2 years ago

3 0

Answer:

Step-by-step explanation:

just olya [345]2 years ago

3 0

Answer:

y-intercept is 0

Step-by-step explanation:

because well you first have to put it in y=mx+b form, after you do that you have -y=0-x and you can't have a -y so you divide by -1 for 0 and -x 0/-1=0 and -x/-1=1 hope that helps

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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

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2 years ago

Is 9,156 divisible by 2,3,4,5,6,9,10

LekaFEV [45]

No, 9,156 divisible by 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84, 109, 218, 327 , 436, 654 , 763, 1308, 1526, 2289, 3052, 4578, and 9156

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2 years ago

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laila [671]

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3 years ago

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ASHA 777 [7]

Answer:

Option 4.) month 4

Step-by-step explanation:

we have

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