Answer:
A = 388.58 cm^2
Step-by-step explanation:
For a cone whose base has a radius R, and a hypotenuse S, the area is:
A = pi*R^2 + pi*R*S
Where pi = 3.14
In this case, we can see that the diameter is: 15cm
Then the radius, half of the diameter, is:
R = 15cm/2 = 7.5cm
The hypotenuse is 9cm, then S = 9cm
A = 3.14*(7.5cm)^2 + 3.14*(9cm)*(7.5cm) = 388.575 cm^2
Rounding to two decimal places, we need to look at the third one, which is a five, so we need to round up:
A = 388.58 cm^2
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
83746+4747+48484=3943848343
Step-by-step explanation:
Easy
Answer:94.2 m
Step-by-step explanation:
Answer:
A(r)=15-3r
Step-by-step explanation:
switch the sign of +3r to make it -3r
