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Semenov [28]
2 years ago
14

Fared wants to enrol in a gym. He has two options, gym A that charges AED 50 as a start-up fee and AED 150 per month and gym B t

hat charges AED 200 per month without a start-up fee. Let m be the number of months. a Which of the following statements represent the algebraic and verbal expressions for the membership fees of both gyms?​
Mathematics
1 answer:
Ymorist [56]2 years ago
3 0

Answer:

hope it help......................

Its A

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The charge to rent a trailer is ​$2525 for up to 2 hours plus ​$99 per additional hour or portion of an hour. Find the cost to r
Ksju [112]

The question is not written properly! Complete question along with answer and step by step explanation is provided below.

Question:

The charge to rent a trailer is ​$25 for up to 2 hours plus ​$9 per additional hour or portion of an hour.

Find the cost to rent a trailer for 2.8 ​hours, 3 ​hours, and 8.7 hours.

Then graph all ordered​ pairs, (hours,​ cost), for the function.

Answer:

ordered pair = (2.8, 34)

ordered pair = (3, 34)

ordered pair = (8.7, 88)

Step-by-step explanation:

Charge for 2.8 ​hours:

$25 for 2 hours

$9 for 0.8 hour

Total = $25 + $9

Total = $34

ordered pair = (2.8, 34)

Charge for 3 ​hours:

$25 for 2 hours

$9 for 1 hour

Total = $25 + $9

Total = $34

ordered pair = (3, 34)

Charge for 8.7 ​hours:

$25 for 2 hours

$9 for 1 hour

$9 for 1 hour

$9 for 1 hour

$9 for 1 hour

$9 for 1 hour

$9 for 1 hour

$9 for 0.7 hour

Total = $25 + $9 + $9 + $9 + $9 + $9 + $9 + $9

Total = $88

ordered pair = (8.7, 88)

The obtained ordered pairs are graphed, please refer to the attached graph.

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3 years ago
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padilas [110]

Answer:

  1. -3
  2. \frac{3}{4}
  3. \frac{-1}{3}
  4. \frac{3}{16}
  5. \frac{3}{10000}

Step-by-step explanation:

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Answer: yes

Step-by-step explanation:

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2 years ago
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1 year ago
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A group of 100 people is divided into 2 teams with 45 people in team A and 55 people in team B.
Zepler [3.9K]
Team A) 45 people
Team B) 55 people

A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A. 
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20

As you can, we get the same answer for both. 

B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22

Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
7 0
2 years ago
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