Answer:
The length of the closed tube is<u> </u>
<u>0.81 m</u>
Explanation:
Formula used :
Speed = v = 346 m/s
wavelength = 0.81 m
<span>The formulas are,
v1d1² = v2d2² ........ (1)
h = (v2²-v1²)/2g ...... (2)
Given that,
v1 = 1.71 m/s
we assume that the stream has decreased by a factor
d2 =0.805d1
then,
v1d1² = v2 (0.805d1)²
cancelled both side d1² then we get,
v1 = v2 (0.805)²
v1 = v2 (0.648025)
Sub v1 = 1.71,
1.71 = v2 (0.648025)
v2 = 1.71/0.648025
v2 = 2.638787083831642
v2 = 2.64 m/s
The vertical distance formula,
h = (v2²-v1²)/2g
We know that value of gravity constant is 9.8 m/s²
h = {(2.64)² - (1.71)²)/2(9.8)
h = {(6.9696) - (2.9241)}/19.6
h = (4.0455)/19.6
h = 0.2064030612244898
h = 0.21 cm
Therefore, the vertical distance h = 0.21 cm.</span>
Answer:
1. Golf ball is in the range of only particulate detectable range
2, alpha partcle is in ultraviolet range of wavelength
3.bullet is in xray range of wavelength
All in the EMW spectrum
Answer:
1.78 J
Explanation:
Find the spring coefficient using Hooke's law:
F = k Δx
23 N = k (0.20 m − 0.14 m)
k = 383.33 N/m
The work is the change in energy:
W = PE₂ − PE₁
W = ½ kx₂² − ½ kx₁²
W = ½ k (x₂² − x₁²)
W = ½ (383.33 N/m) ((0.17 m)² − (0.14 m)²)
W = 1.78 J
Answer:
5.87 m, 75.5°
Explanation:
Let's say C is the resultant vector.
The x component is the sum of the x components of A and B.
Cx = Ax + Bx
Cx = 10.1 cos 60° + 7.3 cos 275°
Cx = 5.69
The y component is the sum of the y components of A and B.
Cy = Ay + By
Cy = 10.1 sin 60° + 7.3 sin 275°
Cy = 1.47
The magnitude is found with Pythagorean theorem, and the angle is found with trigonometry.
C² = Cx² + Cy²
C² = 5.69² + 1.47²
C = 5.87
θ = atan(Cy / Cx)
θ = atan(5.69 / 1.47)
θ = 75.5°