Answer:
Step-by-step explanation:
Given
t = 2 to 7
Required
Find the average speed over these intervals
The function is not given; so, I'll represent the function as s(t)
When 
When 
This gives:
Answer:
0.1569 = 15.69%
Step-by-step explanation:
If eight calls were placed, and we need to know the probability of exactly two calls were occupied, we need to calculate a combination of 8 choose 2 (all the combinations of 2 occupied calls in the 8 total calls), and multiply by the probability of each case in the 8 calls (2 cases occupied and 6 cases not occupied):
P(8,2) = C(8,2) * p(occupied)^2 * p(not_occupied)^6
P(8,2) = (8*7/2) * (0.45)^2 * (0.55)^6
P(8,2) = 28 * 0.2025 * 0.02768 = 0.1569 = 15.69%
Answer:
Step-by-step explanation:
-0.25
-1/3
1/4
0.3
20+0.15x = 35+0.10x
0.15x=15+0.10x
0.05x=15
x= 15/0.05
x= 300minutes
check:
300*.015 = 45+20=65
300*0.10 = 30 + 35 = 65
they equal
so number of minutes would be 300
Answer:
7²b³
Step-by-step explanation:
An exponent signifies repeated multiplication. Here, the factor 7 is repeated twice, and the factor b is repeated 3 times. These will get exponents of 2 and 3, respectively:
7²b³
