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ICE Princess25 [194]
4 years ago
13

How do you calculate the mass of 6 moles of CO2?

Chemistry
1 answer:
Paraphin [41]4 years ago
7 0
The mass<span> of a </span>mole of CO2<span> is approximalty 44 grams. 44*6=264</span>
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HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1.6 × 10−3 at 25∘C If 1.0 M HI is placed into
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Answer:

(B) 0.038 M

Explanation:

Kc = [H2][I2]/[HI]^2

Let the equilibrium concentration of H2 be y M

From the equation of reaction, mole ratio of H2 to I2 formed is 1:1, therefore equilibrium concentration of I2 is also y M

Also, from the equation of reaction, mole ratio of HI consumed to H2 formed is 2:1, therefore equilibrium concentration of HI is (1 - 2y) M

1.6×10^-3 = y×y/(1 - 2y)^2

y^2/1-4y+4y^2 = 0.0016

y^2 = 0.0016(1-4y+4y^2)

y^2 = 0.0016 - 0.0064y + 0.0064y^2

y^2-0.0064y^2+0.0064y-0.0016 = 0

0.9936y^2 + 0.0064y - 0.0016 = 0

The value of y must be positive and is obtained by using the quadratic formula

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