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lisov135 [29]
3 years ago
5

What binary compound would be formed from barium ions and fluoride ions?

Chemistry
2 answers:
geniusboy [140]3 years ago
8 0

Answer:

it is 1,3 and 4

Explanation:

LenaWriter [7]3 years ago
4 0
Barium fluoride (BaF2) - Also known as Barium(II) fluoride - because it's a combination of two different kinds of ions (binary = two).
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Is nitride on the periodic table
sasho [114]

Answer:

yes

Explanation:

Nitride, any of a class of chemical compounds in which nitrogen is combined with an element of similar or lower electronegativity, such as boron, silicon, and most metals.

4 0
3 years ago
Calculate the volume of naoh solution that contains 0.72 g of a 8.0 % (m/v) naoh solution.
Hitman42 [59]
A solution contains 12 g of glucose in 240 mL of solution. What is the mass/volume % of the solution? 5.0% (m/v). Calculate the grams of KCl in 225 g of an 8.00 % (m/m) KCl solution
3 0
3 years ago
Can I mix a sunlight body wash soap and a lemon to get rid of dark spots?​
yuradex [85]

Answer:

Mix ½ teaspoon apple cider vinegar, ½ teaspoon lemon juice, and 1 tablespoon water, and dip a cotton ball in the liquid. Apply to dark

6 0
3 years ago
Limiting Reactant
liraira [26]

Answer:

(1) Cl₂ is the limiting reactant.

(2) 8.18 g

Explanation:

  • 2Na(s) + Cl₂(g) → 2NaCl(s)

First we <u>convert the given masses of reactants into moles</u>, using their <em>respective molar masses</em>:

  • Na ⇒ 12.0 g ÷ 23 g/mol = 0.522 mol Na
  • Cl₂ ⇒ 5.00 g ÷ 70.9 g/mol = 0.070 mol Cl₂

0.070 moles of Cl₂ would react completely with (2 * 0.070) 0.14 moles of Na. There are more Na moles than that, so Na is the reactant in excess while Cl₂ is the limiting reactant.

Then we <u>calculate how many moles of NaCl are formed</u>, <em>using the limiting reactant</em>:

  • 0.070 mol Cl₂ * \frac{2molNaCl}{1molCl_2} = 0.14 mol NaCl

Finally we <u>convert NaCl moles into grams</u>:

  • 0.14 mol NaCl * 58.44 g/mol = 8.18 g
3 0
3 years ago
Consider the reaction when aqueous solutions of potassium hydroxide and ammonium nitrate are combined. The net ionic equation fo
Reil [10]

Answer: OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

KOH(aq)+NH_4NO_3(aq)\rightarrow KNO_3(aq)+NH_3(g)+H_2O(l)

The equation can be written in terms of ions as:

K^+(aq)+OH^-(aq)+NH_4^+(aq)+NO_3^-(aq)\rightarrow K^+(aq)+NO_3^-(aq)+NH_3(g)+H_2O(l)

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The ions which are present on both the sides of the equation are potassium and nitrate ions and hence are not involved in net ionic equation.

Hence, the net ionic equation is :

OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)

6 0
3 years ago
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