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3 years ago

What binary compound would be formed from barium ions and fluoride ions?

Chemistry

2 answers:

geniusboy [140]3 years ago

8 0

Answer:

it is 1,3 and 4

Explanation:

LenaWriter [7]3 years ago

4 0

Barium fluoride (BaF2) - Also known as Barium(II) fluoride - because it's a combination of two different kinds of ions (binary = two).

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What is combustion in physics

NISA [10]

Combustion is a chemical reaction that occurs between a fuel and an oxidizing agent that produces energy, usually in the form of heat and light.

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3 years ago

DONT SKIPP What type of bond will occur between lithium and bromine?

den301095 [7]

An ionic bond is formed between lithium and bromine.

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3 years ago

a radioactive nuclide that is used for geological dating has an atomic number of 19 and mass 40. what is the symbol of this nucl

PIT_PIT [208]

The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K

<h3>Data obtained from the question</h3>

Atomic number = 19
Mass number = 40
Symbol of nuclide =?

<h3>How to determine the nuclide</h3>

From the question given above, the atomic number of the nuclide is 19.

Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K

<h3>How to determine the symbol of the nuclide</h3>

Atomic number (Z) = 19
Mass number (A) = 40
Name of nuclide = Potassium (K)
Symbol of nuclide =?

The symbol of a nuclide is given as ᴬ₂X

Where

A is the mass number
Z is the atomic number
X is the symbol of the element

Thus,

ᴬ₂X => ⁴⁰₁₉K

Therefore, the symbol of the nuclide is ⁴⁰₁₉K

Learn more about composition of atoms:

brainly.com/question/886387

#SPJ1

3 0

2 years ago

What type of reaction is this?<br><br><br><br> N2 + 3H2 → 2NH3

erik [133]

Answer: combination reaction

6 0

3 years ago

If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
------------------------------------------------------------------------------------------------------
Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is $[OH-] = 1 * 10^{-13} mol/L$

Hope this helps!

3 0

4 years ago