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3 years ago

6

One third of a number is 15 less than five sixths of the number. Find the number.

2 answers:

leva [86]3 years ago

4 0

N/3=5n/6 -15

2n/6=5n/6-90/6

2n=5n-90

3n=90

n=30

levacccp [35]3 years ago

3 0

1/3(x) = 5/6(x) - 15
2/6(x) = 5/6(x) - 15
15 = 1/2(x)
x=30

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2 years ago

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3 years ago

This trapezoid has been divided into two right triangles and a rectangle.

jok3333 [9.3K]

The area of the triangle on left is in²: 9

The area of the triangle on the right is in²: 9

The area of the rectangle is in²: 108

The area of the trapezoid is in²: 126

<h3>Area of Compound Shapes</h3>

This exercise requires your knowledge about the area of compound shapes. For solving this, you should:

Identify the basic shapes;
Calculate your individual areas;
Sum each area found.

For finding the area, the steps are presented below.

STEP 1 - Identify the basic shapes.

This trapezoid is composed of two triangles and one rectangle. Therefore, you should sum the area of these geometric figures.

STEP 2 - Find the area of the triangle.

Area of the triangle - $A_{triangle}=\frac{b*h}{2}$ . The figure shows:

b= length of the base= 2in

h=height=9 in

Then, $A_{triangle}=\frac{b*h}{2}=\frac{2*9}{2} =\frac{18}{2}=9 in^2$

Note that the triangles are equals, consequently, they present the same values for the area.

STEP 3 - Find the area of the rectangle.

Area of the rectangle- $A_{rectangle}={b*h}$ . The figure shows:

b= length of the base= 12 in

h=height= 9in

Then, $A_{rectangle}={b*h}=12*9=108 in^2$ .

STEP 4 - Find the area of the trapezoid.

$A_{trapezoid}=2*A_{triangle}+1*A_{rectangle}\\ \\ A_{trapezoid}=2*9+1*108\\ \\ A_{trapezoid}=18+108\\ \\ A_{trapezoid}=126in^2$

Learn more about the area of compound shapes here:

brainly.com/question/15884960

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