Solve 64^x = 16^x−1. 1. x = −2 2 x = −1 3. x = - 1 /4 4. x = negative 1 over 3

Mathematics

2 answers:

DochEvi [55]3 years ago

8 0

$64^x = 16^{x-1} \\\\ (4^3)^x=(4^2)^{x-1} \\\\ 4^{3x}=4^{2x-2}\\\\ 3x=2x-2 \\\\ \boxed{x=-2}$

vova2212 [387]3 years ago

7 0

I am assuming that x - 1 is the exponent of 16

64^x = 16^(x-1)

4^3x = 4^(2x-2)

3x = 2x - 2

x = -2 answer

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