Answer:
$9.45
Step-by-step explanation:
1. First, you want to figure out how much one text message costs. To do this, divide the dollar amount (28.20) by the number of text messages (188). You get 0.15, or $0.15 per text message.
2. Using this $0.15 per text message, you can calculate how much 63 text messages costs. You simply multiply $0.15 by 63 to get $9.45, which is your answer.
Hope this helps! :)
Answer:
y=9x+75
Step-by-step explanation:
since we know that the slope must be the same for two lines to be proportional, we are gonna start there.
so our equation is: y= 9x + b
we need to find b to complete our equation, so substitute in the points we were given.
3 = 9(-8) + b
so now,
3 = -72 + b
now we have to isolate b to find out what it is,
3 = -72 + b
+72 +72
so now: 75= b
Put that back into the starting equation: y = 9x + 75
Answer:
A. 17
B. 16
Step-by-step explanation:
F(5)
5 > 2 so you plug the 5 into 3x+2
F(-2)
-5 < -2 < 2 so you plug the -2 into (x-2)^2
<span>D. One hundred random students from the sixth grade is the best choice given!
</span><span>
Reasons why the other answers and not good choices.
A. The first 100 students from an alphabetical list of the entire school, is incorrect because his only concern is the 6th graders, by including everyone he would negatively skew the data.
B. The first 100 students from an alphabetical list of sixth graders, is incorrect because its unfair to those with names starting later in the alphabet.
C. One hundred random students from the entire school </span>is is better but still incorrect because his only concern is the 6th graders, <span>by including everyone he would again negatively skew the data.</span>
Answer:
Option A: 2338.3 cm² is the correct answer.
Step-by-step explanation:
Given that:
The given figure is a regular hexagon.
Length of side = 30 cm
Area of a hexagon is given by;
Area = 
Putting a=30 in the formula
Area = 
Area = 
Area = 
Area = 2338.26 cm²
Rounding off to one decimal place,
Area = 2338.3 cm²
Hence,
Option A: 2338.3 cm² is the correct answer.
