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Anvisha [2.4K]
2 years ago
11

Line m passes through point (–2, –1) and is perpendicular to the graph of y = –23x + 6. Line n is parallel to line m and passes

through point (4, –3). Which is the equation of line n in slope-intercept form?
Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
3 0

Answer:

y = 1/23x -73/23

Step-by-step explanation:

First, find the slope of line m. Because it is perpendicular, the slope is the opposite reciprocal. So, the slope of line m is 1/23. Now, we know that the slope for line n is 1/23. This is our current equation for line n: y= 1/23x + b. Plug in the point to get this: -3 = 1/23(4) + b. Multiply 1/23 by 4 to get 4/23. This is what it should look like: -3 = 4/23 + b. Subtract 4/23 from both sides to get -3 4/23 = b. Before we plug it back into the equation, we need to change it to an improper fraction, so 23 x 3 equals 69, plus 4 equals 73. So, the improper fraction is -73/23. Go back to our original equation and plug in -73/23 for b. This is your final equation for n: y = 1/23x -73/23. Hope this helped!

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