Answer:
A. 1/5
Step-by-step explanation:
Add all the numbers up, you get 25. There is 5 yellow marbles, so that's a 5/25 chance of picking a yellow one, now you just have to simplify, you then get 1/5, because 5 ÷ 5 is 1, and 25 ÷ 5 is 5.
Answer:
110
Step-by-step explanation:
Using pythagorean theorm
c^2 = a^2 + b^22
610^2 = 600^2 + b^2
372100 = 360000 + b^2
b^2 = 12100
b = 110
For #1 the answers are
69 degrees
155 degrees
86 degrees
335 degrees
249 degrees
<h2>25 </h2>
Step-by-step explanation:
<h3><em>=</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>(</em><em>5</em><em> </em><em>-</em><em> </em><em>1</em><em>)</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>1</em><em>2</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>2</em><em>5</em></h3>
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Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!