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Charra [1.4K]
3 years ago
10

Pls answer 6≥ h/2 .............................

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
3 0

$6-3x<12\quad:\quad\begin{bmatrix}\mathrm{Solution:}\:&\:x>-2\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-2,\:\infty\:\right)\end{bmatrix}$6−3x<12    :    [ Solution:   x>−2   Interval Notation:  (−2, ∞ ) ]

Steps

$6-3x<12$6−3x<12

$\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}$Subtract 6 from both sides

$6-3x-6<12-6$6−3x−6<12−6

$\mathrm{Simplify}$Simplify

$-3x<6$−3x<6

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$Multiply both sides by −1 (reverse the inequality)

$\left(-3x\right)\left(-1\right)>6\left(-1\right)$(−3x)(−1)>6(−1)

$\mathrm{Simplify}$Simplify

$3x>-6$3x>−6

$\mathrm{Divide\:both\:sides\:by\:}3$Divide both sides by 3


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