The interest in the first month is given as $ 97.1. The principal balance in the second question is $15,030.02
<h3>How to solve for the interest in the first month</h3>
1. We have to solve for the cost of the car
This would be = 19,725*(1.0475)
= 20,661.9375
There is a Down payment = 2,175
balance would be 20661.9375-2,175 = 18,486.94
average rating interest of new car = 6.30%
So the interest accrued in first month = 18,486.94x0.063/12 = $ 97.1
2. cost = 15867
sales tax = 5.25%
10 percent down payment
5.25/100 = 0.0525
cost of car = 15867 + (15867 * 0.0525)
= 16700 dollars
10% of 16700 dollars
= 1670 dollars
principal balance = 16700 - 1670
= $15,030.02
Read more on interest rate here
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Answer and Step-by-step explanation:
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1. Let's write out the equation to subtract.
7t - 2u - 3v - (t - 3v)
Distribute the negative to the t and -3v.
7t - 2u - 3v - t + 3v (The negatives cancel out)
Now simplify by combining like terms.
6t - 2u
This is the answer because the 3v and -3v cancel out.
2. I don't really understand what this is saying. Is there answer choices for this? But what I think its saying is that the lift has a constant of 2.
3. To find out the amount of terms, we would simplify the equation.
2x + 3y - 5x + yz - x
-4x + 3y + yx
Here, we can see that we have 3 terms in this expression.
-4x is the first term, +3y is the second term, and +yx is the third term.
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#teamtrees #WAP (Water And Plant)
Answer: b=13, t=29
Step-by-step explanation:
Substituting the first equation into the second,
Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
Answer:
the answer is 10.7
Step-by-step explanation:
that show give you your answer
