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ehidna [41]
2 years ago
5

How many solutions -3x+9-2x=-12-5X

Mathematics
1 answer:
vesna_86 [32]2 years ago
5 0

Answer:

0

Step-by-step explanation:

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Simplify question question 18<br><br> ILL MARK BRAINLIST
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Answer:

x^9y^3

Step-by-step explanation:

Step 1: Write expression

(\frac{x^{\frac{3}{4} }}{y^{\frac{-1}{4} }} )^{12}

Step 2: Simplify Parenthesis

(x^{\frac{3}{4} }}{y^{\frac{1}{4} }} )^{12}

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4 0
3 years ago
Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe
AlekseyPX
The answer is
\frac{-6i-3}{5}.

Before we rationalize the denominator, we must simplify the numerator and denominator.  We evaluate the square root on the top, and combine like terms on the bottom:
\frac{\sqrt{-9}}{(4-7i)-(6-6i)}&#10;\\&#10;\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}&#10;\\&#10;\\=\frac{3i}{-2-i}

To rationalize the denominator, we multiply by the conjugate.  The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign.  The conjugate of -2-i is -2+i:

\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}&#10;\\&#10;\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}&#10;\\&#10;\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}&#10;\\&#10;\\=\frac{-6i+3i^2}{4-2i+2i-i^2}&#10;\\&#10;\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}
7 0
3 years ago
Help answer ASAPPP 10 points
Musya8 [376]
Time:logs=time:logs
time/logs=time/logs

4hours:6logs=18hours:xlogs
4hours/6logs=18hours/xlogs
4/6=18/x
6/4=18/x
x=27

pick B,C,E
8 0
3 years ago
Read 2 more answers
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