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2 years ago

Evaluate: (3)-3? Question 1 options: A-9 B-1/27 C 1/27

Mathematics

2 answers:

PIT_PIT [208]2 years ago

7 0

The answer is A or option one.

Hope This Helps and God Bless!

soldier1979 [14.2K]2 years ago

5 0

The answer to this question is A.

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1.19<br> 1.8<br> 1.09 <br> smallest to biggest

Misha Larkins [42]

Answer:

1.09 , 1.19 , 1.8

Step-by-step explanation:

all in order

6 0

2 years ago

Read 2 more answers

The graphs of the functions f(x)=|x-3| + 1 and G(x)=2x + 1 are drawn. which statement about these functions is true?

Roman55 [17]

The only true statement that compares the two functions is:

B: The solution to f(x)=g(x) is 1

<h3>Which statements are correct?</h3>

Here we have the functions:

f(x) = |x - 3| + 1

g(x) = 2x + 1

First, let's find the solution for:

f(x) = g(x)

|x - 3| + 1 = 2x + 1

|x - 3| = 2x

Notice that we have two options, x = 3:

|3 - 3| = 2*3

0 = 6 (x = 3 is not a solution)

And x = 1:

|1 - 3| = 2*1

2 = 2 (x = 1 is a solution).

Now to get the y-value where the graphs intersect, we just evaluate one of the functions in the solution we found above;

f(1) = |1 - 3| + 1 = 2 + 1 = 3

The graphs intersect when y = 3.

Then we conclude that the only true statement is:

B: The solution to f(x)=g(x) is 1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

8 0

2 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

2 years ago

HELP PLEASE

vredina [299]

The answer to you question is B for number 1 and for 2 it is C. Hope this helps

4 0

3 years ago

Read 2 more answers

Figure LMNO is a parallelogram.<br> What is the value of x?

galina1969 [7]

Values is 6 for lmso is a parellelle gram

3 0

2 years ago