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Lana71 [14]
3 years ago
12

One number is 2 more than another. The difference between their squares is 52. What are the numbers?

Mathematics
2 answers:
vova2212 [387]3 years ago
6 0

Answer:

The aprox, numbers:

4.1633   and    8.3266

Step-by-step explanation:

a = 2b

a² - b² = 52

then:

(2b)² - b² = 52

4b² - b² = 52

3b² = 52

b² = 52/3

b² = 17.333

√b² = √17.333

b = 4.1633        aprox.

a = 2b

a = 2*4.1633

a = 8.3266

Check:

8.3266² - 4.1633² = 52

69.333 - 17.333 = 52

kirza4 [7]3 years ago
4 0
The numbers are 12 and 14.
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- 7h + 2(-4h +5) > -4h +1 +10. Solve for h​
navik [9.2K]

Hello.

-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h

Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.

-7h - 8h + 10 > -4h + 11

Add like terms.

-15h + 10 > -4h + 11

Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.

Subtract 10 from both sides. Then, add 4h to both sides.

-15h + 4h > 11 - 10

Simplify.

-h > 1

Divide both sides by -1.

However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <

-h ÷ -1 < 1 ÷ -1

h < -1

6 0
3 years ago
(08.02)a pair of equations is shown below. 3x − y = 9 y = −2x + 11 if the two equations are graphed, at what point do the lines
mixas84 [53]
3x - y = 9
y = -2x + 11

3x - (-2x + 11) = 9
3x + 2x - 11 = 9
3x + 2x = 9 + 11
5x = 20
x = 20/5
x = 4

y = -2x + 11
y = -2(4) + 11
y = -8 + 11
y = 3

solution (where the lines intersect) is (4,3)
8 0
3 years ago
Read 2 more answers
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
Segu
Lynna [10]

Answer:

The formula is 10 - 3n

Step-by-step explanation:

For an nth term in an arithmetic sequence

U( n ) = a + ( n - 1)d

Where n is the number of terms

a is the first term

d is the common difference

From the sequence above

a = 7

d = 4 - 7 = - 3

The formula for an nth term is

U(n) = 7 + (n - 1)-3

= 7 - 3n + 3

The final answer is

= 10 - 3n

Hope this helps you.

3 0
3 years ago
Saige's spaceship traveled 588 588588 kilometers ( km ) (km)left parenthesis, start text, k, m, end text, right parenthesis in 6
pshichka [43]

Answer:

The first ship has the same speed as Saige's ship while the second and third do not have the same speed.

Step-by-step explanation:

d = Distance traveled by Saige's spaceship = 588 km

t = Time taken = 60 seconds

Speed is given by

s=\dfrac{d}{t}\\\Rightarrow s=\dfrac{588}{60}\\\Rightarrow s=9.8\ \text{km/s}

The other ships

s=\dfrac{441}{45}=9.8\ \text{km/s}

s=\dfrac{215}{25}=8.6\ \text{km/s}

s=\dfrac{649}{110}=5.9\ \text{km/s}

So, the first ship has the same speed as Saige's ship while the second and third do not have the same speed.

8 0
3 years ago
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