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OlgaM077 [116]
3 years ago
7

How does organisms get the energy needed

Chemistry
1 answer:
cluponka [151]3 years ago
7 0

Answer:they get it though food!

Explanation:

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What is the sum of 16+ -20?
mr Goodwill [35]

Answer:

-4

Explanation:

PLz give me brainliest I worked hard thank u

6 0
3 years ago
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For which of the following processes would you expect there to be an increase in entropy? Ag+(aq) + Cl-(aq) AgCl(s) H2O(g) H2O(l
Lyrx [107]
CaBr₂(s) → Ca⁺²(aq) + 2Br⁻ (aq)     ΔS>0
6 0
3 years ago
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Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4
Helga [31]

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

  • 27+31+16(4)
  • 58+48
  • 106u

Moles of AlPO_4

  • 61µg/106
  • 0.000061/106
  • 5.75×10^{-7}
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Moles of Al3+=57.5µmol

3 0
3 years ago
Which question cannot be answered by science?
Bumek [7]
Hi!

The question that science cannot answer is any question which is opinionated. It cannot have one true answer because it is simply subjective.

Other examples would be any question which cannot successfully follow the scientific method.

So, in the case of the question - the answer is going to be whichever question is <em>opinionated. </em>Just as a hint, not <em>everyone </em><em>thinks </em>endangered animals <em>should </em>be protected. 

Hopefully, this helps! =)
5 0
3 years ago
An archaeologist graduate student found a leg bone of a large animal during the building of a new science building. The bone had
Vlad [161]

Answer : The time passed in years is 2.74\times 10^2\text{ years}

Explanation :

Half-life of carbon-14 = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant disintegrate = 15.3

a - x = amount left after decay process = 14.8

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{15.3}{14.8}

t=274.64\text{ years}=2.74\times 10^2\text{ years}

Therefore, the time passed in years is 2.74\times 10^2\text{ years}

4 0
4 years ago
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