Answer:
We are heating the sample repeatedly to become a pure compound of only MgSO4 (withot H2O) and a constant mass.
Explanation:
Step 1: Data given
Mass of MgSO4·7H2O = 5.06 grams
The remaining MgSO4 had a constant mass of 2.47 grams.
Step 2: Explain why the sample in the crucible was heated repeatedly until the sample had a constant mass.
Before heating the compound has magnesium sulfate and water.
The total mass of this compound is 5.06 grams
By heating we try to eliminate the water.
After heating there remain mgSO4 with a mass of 2.47 grams
This means 5.06 - 2.47 = 2.59 grams is water. All of this is eliminated.
The heating process happens repeatedly to make sure the final compound is pure. So the 2.47 grams os only MgSO4. If the mass would not be constant. It means the compound is not pure, the not all the water is eliminated yet.
So we are heating the sample repeatedly to become a pure compound of only MgSO4 (withot H2O) and a constant mass.
Answer:
The answer to your question is below
Explanation:
There are 4 laws of gases
- Charles
- Gay Lussac
- Boyle - Mariotte
P1V1 = P2V2
- General law of gases
Let's use these formulas to answer the question
p2 = V2/P1 This is not a law of gases
p1= V1/k This formula is similar to Boyle mariotte equation
but is not.
V2 = k/P2 This equation is correct is Boyle Mariotte formula
V2 = P1V1/ P2 This equation is also correct is Boyle Mariotte formula
V1 = P1/P2 (V2) This equation is incorrect
P2 = (P1) V1/V2 This equation is correct is Boyle mariotte formula
Answer:
136.36 mL
Explanation:
Here we have to use the dilution formula
From C1V1= C2V2
Where;
C1= initial concentration of the solution= 12.0 M
C2= final concentration of the solution= 2.20 M
V1 = initial volume of the solution= 25.0 ml
V2= final volume of the solution= ?????
Then recall;
C1V1=C2V2
V2 = C1V1/C2
Substituting values from the parameters given;
V2= 12.0 × 25.0 / 2.20
V2= 136.36 mL
The one with the smaller mass because they have the same force but one is lighter
