All categories

3 years ago

How does your body use perspiration to stay cool

2 answers:

7 0

Imagine each of those as a drop of sweat that will evaporate taking a bit of your body heat away. So sweat helps cool you down two ways. First, it makes your skin feel cooler when it's wet. And when it evaporates it removes some heat.

serg [7]3 years ago

6 0

Sweat helps you cool down 2 ways. First, when you sweat it makes your skin feel cool because it's wet . Also when is evaporates it releaves some heat.

You might be interested in

Please help me! This is too hard!?

Annette [7]

Answer: 59.24 atm

Explanation:

Given that:

Original Volume of gas V1 = 2.7L

Temperature T1 = 42.7°C

Convert Celsius to Kelvin

(42.7°C + 273 = 315.7K)

Pressure P1 = 684.9 torr

Final Volume V2 = 0.14 L

Final temperature T2 = 803.1°C

Convert Celsius to Kelvin

(803.1°C + 273 = 1076.1K)

Final pressure = ?

Then, apply the combined gas equation

(P1V1)/T1 = (P2V2)/T2

(684.9 torr x 2.7L)/315.7K = (P2 x 0.14L)/1076.1K

1849.23/315.7 = 0.14P2/1076.1

Then, cross multiply

1849.23 x 1076.1 = 315.7 x 0.14P2

1989956.403 = 44.198P2

Divide both sides by 44.198

1989956.403/44.198 = 44.198P2/44.198

45023.67 torr = P2

Now, convert the pressure in torr to atmosphere

If 760 torr = 1 atm

45023.67 torr = Z atm

Then, cross multiply

760 torr x Z = 45023.67 torr x 1 atm

Z = 45023.67 torr / 760 torr

Z = 59.24 atm

Thus, the new pressure of the gas will be 59.24 atm

5 0

4 years ago

What is the conclusion of an experiment

Misha Larkins [42]

The conclusion includes a summary of the results, whether or not the hypothesis was supported, the significance of the study, and future research.

6 0

3 years ago

Read 2 more answers

The mole fraction of a non electrolyte (MM 101.1 g/mol) in an aqueous solution is 0.0194. The solution's density is 1.0627 g/mL.

yanalaym [24]

Answer:

Molarity for the solution is 1.05 mol/L

Explanation:

Mole fraction of solute = 0.0194

Solution's density = 1.0627 g/mL

We must know that sum of mole fraction = 1

Mole fraction of solute + Mole fraction of solvent = 1

0.0194 + Mole fraction of solvent = 1

Mole fraction of solvent = 1 - 0.0194 → 0.9806

Molarity is mol of solute in 1L of solution, so we have to determine solution's volume in L

With molar mass we can determine the mass of solute and solvent and then, the solution's mass

0.0194 mol . 101.1 g/ mol = 1.96 g of non electrolyte solute

0.9806 mol . 18 g/mol = 17.65 g of water

Mass of solution = mass of solute + mass of solvent

1.96 g + 17.65 g = 19.6 g (mass of solution)

Solution's density = Solution's mass / Solution's volume

1.0627 g/mL = 19.6 g / Solution's volume

Solution's volume = 19.6 g / 1.0627 g/mol →18.4 mL

Let's convert the mass from mL to L

18.4mL . 1L / 1000 mL = 0.0184 L

We have the moles of solute, so let's determine molarity

mol/L → 0.0194 mol / 0.0184 L = 1.05 M

8 0

3 years ago

The heat index temperature:___________ a. bines air pressure and temperature in a comfort index b. bines relative humidity and t

kvasek [131]

Answer:

bines relative humidity and temperature in a comfort index

Explanation:

The Heat Index temperature measures how hot it feels when humidity is factored with the air temperature.

It is important for the human body's comfort.

The human body feels warmer in humid conditions it begins to perspire or sweat to cool itself off when the body gets too hot.

The concept of the heat index was developed by George Winterling in 1978.

The heat index temperature makes assumptions regarding the human body mass and height, clothing, amount of physical activity etc.

The heat index temperature bines relative humidity and temperature in a comfort index.

6 0

3 years ago

what does the number of the places after the decimal in a measurement tell you about the precision of the instrument that record

snow_lady [41]

The more numbers after the decimal point there are, the more precise the instrument which recorded it is. For example, if one instrument during seismic activity records that the magnitude of the earthquake was 2.3, and another instrument recorded that it was 2.3645, the second instrument would have shown to be more precise.

3 0

3 years ago