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2 years ago

What is the conclusion of an experiment

2 answers:

6 0

The conclusion includes a summary of the results, whether or not the hypothesis was supported, the significance of the study, and future research.

Masja [62]2 years ago

4 0

I just took the test for that but forgot um I believe it was like gas I don't know I did not just take it was last week

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Conduction and Convection involve the movement of particles. Radiation does not True or False

Rom4ik [11]

Answer:

False

Explanation:

Because it is false heat will always transfer so it require matter

6 0

3 years ago

Read 2 more answers

Which element is this.Its shiny,Is solid at room temperature, has atoms with two valence electrons?A:Lithium B:Strontium C:Alumi

tatyana61 [14]

Answer:

Stronium

Explanation:

It is a metal (and shows classic physical proerties). It also belongs to the second family, meaning it has two valence electrons.

4 0

3 years ago

What is the density if a sample of rock has a mass of 69 g and a volume of 23 ml?

kiruha [24]

Density = mass / volume

= 69g / 23 ml

= 3 g / ml.

Thus, the density of the sample is 3 grams per ml or 3g/ ml

4 0

3 years ago

Read 2 more answers

What range on the glycemic index (GI) corresponds to a high glycemic impact food? 70 and above 56 to 69 1 to 55 1 to 35

german

Answer: 70 and above

Explanation:

This is a fact.

8 0

1 year ago

Which of these half-reactions represents reduction?

gogolik [260]

Answer: The half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element takes place is called reduction-half reaction.

For example, the oxidation state of Cr in $Cr_{2}O^{2-}_{7}$ is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

$Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}$

Similarly, oxidation state of Mn in $MnO^{-}_{4}$ is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

$MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}$

Thus, we can conclude that half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

3 0

3 years ago