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3 years ago

Explain how human activity can affect the carbon cycle.

Chemistry

2 answers:

bazaltina [42]3 years ago

8 0

Answer:

Sample Response: Human activity can affect the amount of carbon in the atmosphere. When fossil fuels like oil, coal, and natural gas are burned, carbon dioxide is released into the atmosphere as waste. The clearcutting of forests for lumber and fuel also increases levels of carbon dioxide in the atmosphere because the trees can no longer remove carbon dioxide from the atmosphere for photosynthesis. If trees are burned in order to be cleared, the burning processes release even more carbon dioxide into the air.

Explanation:

Eva8 [605]3 years ago

4 0

Answers:

Human activities badly affect carbon cycle. Activities such as burning fossil fuel and deforestation have begun to effect on carbon cycle and the rise of carbon dioxide in atmosphere.

Explanation:

The carbon cycle can be affect when carbon dioxide is either released into atmosphere or remove from atmosphere. When fossil are burnt , carbon is release to the atmosphere at faster rate then it is removed. Natural gas, oil, coal, and other industrial products all are affecting carbon cycle in atmosphere.

Deforestation means permanent removal of trees from forest which cause increase in level of carbon dioxide because no trees longer to absorb carbon dioxide from atmosphere. Which result affect on carbon cycle.

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Oxygen and tin 4 chloride react form chlorine and tin 3 oxide

Deffense [45]

Your question wasn’t very clear, but that isn’t right.

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2 years ago

The stimulus is related to?

Flura [38]

Answer:

The government :) lol

Explanation:

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2 years ago

Gaseous hydrogen and oxygen can be prepared in the laboratory from the decomposition of gaseous water. The equation for the reac

nata0808 [166]

Answer:

$m_{O_2}=87.2gO_2$

Explanation:

Hello.

In this case, given the chemical reaction, we can compute the grams of oxygen by using the 98.2 g of water via the 2:1 mole ratio between them, the molar mass of water that is 18.02 g/mol, the molar mass of gaseous oxygen that is 32.00 g/mol and the following stoichiometric procedure relating the given information:

$m_{O_2}=98.2gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molO_2}{2molH_2O}*\frac{32.00gO_2}{1molO_2} \\\\m_{O_2}=87.2gO_2$

In which the result is displayed with three significant figures because the given mass of water 98.2 g, has three significant figures too.

Best regards!

6 0

2 years ago

How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?

gulaghasi [49]

Answer:

$\boxed {\boxed {\sf 10.2 \ kJ}}$

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

$q=mc \Delta T$

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

m= 225 g
c= 0.897 J/g° C
ΔT= 50.5 °C

$q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

Multiply the first two numbers. The units of grams cancel.

$q= (225 \ g * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

$q= (225 * 0.897 \ J / \textdegree C)(50.5 \textdegree C)$

$q= (201.825\ J / \textdegree C)(50.5 \textdegree C)$

Multiply again. This time, the units of degrees Celsius cancel.

$q= 201.825 \ J * 50.5$

$q= 10192.1625 \ J$

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

$\frac { 1 \ kJ}{ 1000 \ J}$

Multiply by the answer we found in Joules.

$10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}$

$10192.1625 * \frac{ 1 \ kJ}{ 1000 }$

$\frac {10192. 1625}{1000} \ kJ$

$10.1921625 \ kJ$

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

$10.2 \ kJ$

Approximately <u>10.2 kilojoules</u> of energy would be required.

3 0

2 years ago

Which Statements below are true?

yKpoI14uk [10]

A. If motion starts and stops at the same location, then the displacment is zero.

D. Distance is always greater than or equal to the magnitutde of the displacement.

7 0

3 years ago