Solution :
It is given that a psychologist wants to determine the difficulty of the task influences on the estimate of how long people spend working on it.
Now we have to describe a experiment by using a completely randomized design and learn the effect of the difficulty on the estimated time is by randomly assigning 15 students to a Group 1 of easy mazes and other 15 students to the second group 2 of hard mazes. And then we compare the time estimates of the two groups.
Answer:7.125 min
Step-by-step explanation:
Given
Resting time =24 min
Personal time=10 min
Delay=14 min
Observed Time=6min/cycle
Performance Rating=95%
Allowance Time=Rest time+Personal time+delay
Allowance time=24+10+14=48 min
Allowance Factor=
Calculate the Normal Time
Normal time=Observed time
personal Time=6\times 0.95=5.7 min
Standard time=Normal time 
Allowance Factor
Standard time =
=7.125 min
From the points you get a slope of -1 using the slope in y=mx+b you get b=1 so y=-x+1
9x8y12 it a lot of work to do so I don't want to type how to do the problem
Answer:
27 chickens
Step-by-step explanation:
A chicken farmer also has cows for a total of 30 animals
Both animals have a total of 66 legs
Let a represent the number of chicken
Let b represent the number of cows
a + b= 30........equation 1
Since a chicken has only two legs and a cow has four leg then, the expression can be represented as
2a + 4b= 66........equation 2
From equation 1
a + b= 30
a = 30-b
Substitute 30-b for a in equation 2
2a + 4b= 66
2(30-b) + 4b= 66
60 - 2b + 4b= 66
60 + 2b= 66
2b= 66-60
2b= 6
b= 6/2
b= 3
Substitute 3 for b in equation 1
a + b = 30
a + 3=30
a= 30-3
a= 27
Hence the farmer has 27 chickens
