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3 years ago

Given a line segment that contains the points A,B, & C in order, if AB = x, BC = x, and AC is equal to 36, then x = _____.

Mathematics

1 answer:

Bumek [7]3 years ago

6 0

Answer:

a. 18

Step-by-step explanation:

AB+BC = AC

x + x = 36

2x = 36

x = 36/2

x = 18

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frutty [35]

I believe The answer is B

6 0

3 years ago

HELP PLEASE!!

zhenek [66]

Answer:

y = 1/2x + 1.

Step-by-step explanation:

Use the point-slope form of a straight line:

y - y1 = m(x - x1) (where m=slope and(x1,y1) is a point on line).

y - 3 = 1/2(x - 4)

y = 1/2x - 2 + 3

y = 1/2x + 1.

7 0

3 years ago

Pls help me ...........

zaharov [31]

Answer:

19657

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

1. Writing an equation for an exponential function by

Naya [18.7K]

Answer: 1) $t(n)=0.6(2)^n$

2) $f(x)=10(5)^x$

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

$t(n) = ab^n$ ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

$0.6 = a(b)^0\implies 0.6 = a$

Hence the function that shows the given situation,

$t(n) = 0.6 b^n$ -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

$1.2 = 0.6 b^1\implies 2 = b$

Thus, the complete function is,

$t(n) = 0.6 (2)^n$

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = ab^x$ ---------(1)

For f(x) = 2, x = -1

By equation (1),

$2= ab^{-1}$ ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

$\frac{2}{5}= a(b)^{-2}$

$\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}$

$\implies \frac{2}{5}=\frac{2}{b}$

$\implies 2b=10$

$\implies b = 5$

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = 10(5)^x$

5 0

3 years ago

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

guapka [62]

Answer:

The least possible result is <em>-10</em>.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

$A(B-C) = 4 \times (5-6) = 4 \times -1 = -4$

Let A = 4, B = 6 and C = 5

$A(B-C) = 4 \times (6-5) = 4 \times 1 = 4$

Let A = 5, B =4 and C = 6

$A(B-C) = 5 \times (4-6) = 5 \times -2 = -10$

Let A = 5, B = 6 and C = 4

$A(B-C) = 4 \times (6-4) = 4 \times 2 = 8$

Let A = 6, B = 4 and C = 5

$A(B-C) = 6 \times (4-5) = 6 \times -1 = -6$

Let A = 6, B = 5 and C = 4

$A(B-C) = 6 \times (6-5) = 6 \times 1 = 6$

Summarizing the above values in the form of a table:

$\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\ 4 & 6 & 5 & 4\\ 5 & 4 & 6 & -10\\ 5 & 6 & 4 & 10\\ 6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}$

So, the least possible result is <em>-10</em>.

3 0

3 years ago