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oksano4ka [1.4K]
2 years ago
12

In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the

probability that the memory and the hard disk fail simultaneously is 0.0014, then
(a) Are memory failures and hard disk failures independent events?
Mathematics
1 answer:
ratelena [41]2 years ago
8 0

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

P(A) = 0.01 , P(B) = 0.02

We also know the probability that the memory and the hard drive fail simultaneously given by:

P(A \cap B) = 0.0014

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

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Answer:

A. 106 + 2x + 50 = 180

Step-by-step explanation:

A. 106 + 2x + 50 = 180. Correct.

B. 2x + 50 = 180. Incorrect. Angle is not a Straight Angle.

C. 2x + 50 = 106. Incorrect. That equals the first angle.

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4 0
2 years ago
A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
Katie wants to buy 27 candles. If there are 9 candles in each box, how many boxes of candles should Katie buy? * (need the answe
cricket20 [7]

Answer:

3 boxes

Step-by-step explanation:

because 3 times 9 is 27.

3 0
3 years ago
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Slav-nsk [51]
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you will put 30 instead of X in each equation and see which one is the cheapest
you put 30 beacuse it is said 30 miles and also said That X is the mile
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6 0
3 years ago
Complete the proof by providing the missing reasons. given:cb bisects bd,de bisects ec, cb=de. prove dbc=ced. . . CB=DE,CB BISEC
Alexus [3.1K]
Base on your question were the are proofs that is given are this are: CB bisects BD, DE bisects EC, CB=DE. So answer your question you must understand first your given statements and realize that CBD and DEC are both right triangles because they are a perpendicular segment so i conclude that the answer should be CBD=DEC because they are both right angles
5 0
2 years ago
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