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Deffense [45]
3 years ago
10

Determine the value of x. 30° 45° 20° 60°

Mathematics
1 answer:
barxatty [35]3 years ago
7 0

Answer:

x=30

Step-by-step explanation:

x+2x+3x=180

6x=180

x=180/6=30

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Mauricio scored a total of 34.42 points in five gymnastic
Olegator [25]

Answer:

Mauricio's score for each event is 7.

Step-by-step explanation:

Mauricio scored a total of 34.42 points in five gymnastic  events.

We can round off his score as 35.

To find Mauricio's score for each event, divide total score and no of events as follows :

n=\dfrac{35}{5}\\\\=7

Hence, Mauricio's score for each event is 7.

3 0
3 years ago
Consider the volume of the region shown below, which shows a right circular cone with top radius 3 cm and height 10 cm. We have
koban [17]
I have the same problem here with a slight change in the given values:

radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3.... 

<span>thus the [ π radius ² thickness ] yields π (y² / 9 ) <span>dy ,</span> y in [ 0 , 6 ] for the volume... </span>

a Riemann sum is then : y_i = 0 + i [ 6 / n ] = 6 i / n , i = 1,2,3...n and do a right side sum 

<span>π Σ { i = 1,2,3..n } [ 36 i² / 9 n² ] [ 6 / n ]
</span>
I hope my guide has come to your help. God bless and have a nice day ahead!
5 0
3 years ago
Evaluate to earn 10 points and brainliest
Helga [31]

Answer: -8

Step-by-step explanation:

if y=6x+(-2),  than y= 6x-2

if x=-1 we will replace x with this value

y=6(-1)-2=-6-2=-8

5 0
3 years ago
Which number is composite? 53,81,41,47,31<br><br> a. 31<br><br> b. 81<br><br> c. 41<br><br> d. 47
Eduardwww [97]

answer

B 81

explanation

6 0
3 years ago
What is the product of -2x^3+x-5 and x^3-3x-4 ?
murzikaleks [220]
To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
6 0
3 years ago
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