7,15,19,34 are not multiples of four. to find this answer out just divide four into them.
V ,= 4/3 πr³
solve for r
3V/4=r³
so r is the cubed root of 3V/4
<h3>
Answer: y^4 - 2y^3 + 7y^2 + y - 5</h3>
Work Shown:
h(y) = f(y) + g(y)
h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)
h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2
h(y) = y^4 + (-3y^3+y^3) + 7y^2 + y + (-3 - 2)
h(y) = y^4 - 2y^3 + 7y^2 + y - 5
This is a fourth degree polynomial (aka quartic).
Answer:
do it yourself
Step-by-step explanation:
Answer:
<h2><em><u>2a</u></em></h2>
Step-by-step explanation:
(a+b-c)-(b-a-c)
= a + b - c - b + a + c
= a + a + b - b - c + c
= <em><u>2a (Ans)</u></em>
