Positive electric charge Q is distributed uniformly along a thin rod of length 2a. The rod lies along the x-axis between x = -a
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The magnitude of the current in wire 3 is 2.4 A and in a direction pointing in the downward direction.
- The force per unit length between two parallel thin current-carrying
and
wires at distance ' r ' is given by
....(1) .
- If the current is flowing in both wires in the same direction, and the force between them will be the attractive force and if the current is flowing in opposite direction in wires then the force between them will be the repulsive force.
A schematic of the information provided in the question can be seen in the image attached below.
From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3
Using equation (1) , we get
I₃ = 2.4 A and the current is pointing in the downward direction
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Answer:
Here is the complete question:
https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632
a) Current for long straight wire
b) Current at the center of the circular coil
c) Current near the center of a solenoid
Explanation:
⇒ Magnetic Field due to long straight wire is given by (B),where
Plugging the values,
Conversion ,and
⇒Magnetic Field at the center due to circular coil (at center) is given by,
So
⇒Magnetic field due to the long solenoid,
Then
So the value of current are ,
and
respectively.