Answer:
a) , b)
Explanation:
a) The heat transfered to the egg is computed by the First Law of Thermodynamics:
b) The amount of entropy generation is determined by the Second Law of Thermodynamics:
Positive electric charge Q is distributed uniformly along a thin rod of length 2a. The rod lies along the x-axis between x = -a
1 answer:
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Answer:
Explanation:
Given that,
A point charge is placed between two charges
Q1 = 4 μC
Q2 = -1 μC
Distance between the two charges is 1m
We want to find the point when the electric field will be zero.
Electric field can be calculated using
E = kQ/r²
Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.
Then, the magnitude of the electric at point x is zero.
E = kQ1 / r² + kQ2 / r²
0 = kQ1 / x² - kQ2 / (1-x)²
kQ1 / x² = kQ2 / (1-x)²
Divide through by k
Q1 / x² = Q2 / (1-x)²
4μ / x² = 1μ / (1 - x)²
Divide through by μ
4 / x² = 1 / (1-x)²
Cross multiply
4(1-x)² = x²
4(1-2x+x²) = x²
4 - 8x + 4x² = x²
4x² - 8x + 4 - x² = 0
3x² - 8x + 4 = 0
Check attachment for solution of quadratic equation
We found that,
x = 2m or x = ⅔m
So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.
Answer:
0.0334N
Explanation:
Given parameters:
M1 = 5 x 10⁶kg
M2 = 1 x 10⁶kg
Distance = 100m
Unknown:
Gravitational force = ?
Solution:
To solve this problem, we use the Newton's law of universal gravitation.
Fg =
G is the universal gravitation constant
m is the mass
r is the distance
Fg = = 0.0334N