The oceanic crust slides under the continental crust due to the differences in their densities. The continental rust is more felsic (contains more silica) which makes it lighter than the oceanic crust which is more mafic (contains more fe and mg)<span />
Answer:
318 Earth-pull
Explanation:
Using Newton's law of gravitational force
F = GMm / r²
F is directly proportional to mass
let earth = m
then m .......... Earth-pull
318 m = 318 m × Earth-pull / m = 318 Earth-pull
Given Information:
Diameter = d = 100 m
Required Information:
Period = T = ?
Answer:
Period = T = 14.2 seconds
Explanation:
We know that a station revolving at an angular velocity ω, have an acceleration given by
α = ω²r
Where ω is angular velocity and r is the radius of cylindrical space station.
Normal gravity means α = g = 9.8 m/s²
ω² = α/r
ω = √(α/r)
The radius is given by
r = d/2
r = 100/2
r = 50 m
ω = √(9.8/50)
ω = 0.4427 rad/sec
We also know that
ω = 2πf
f = ω/2π
f = 0.4427/2π
f = 0.0704 rev/sec
Finally time period is given by
T = 1/f
T = 1/0.0704
T = 14.2 sec
Therefore, the rotation period is 14.2 seconds.
To solve this problem it is necessary to apply the related concepts to the principle of overlap, specifically to single slit diffraction experiment concept.
Mathematically this can be expressed as:
Where,
d = Width of the slit
Wavelength
Angle relative to the original direction of the light
m = Any integer which represent the order of the equation (number of repetition of the spectrum)
To solve the problem we need to rearrange the equation and find the wavelength
Our values are given as,
Replacing in our equation we have,
Therefore the wavelength is 523.2nm
1. 7.1111m/s Recurring
Solution a = v/t basically divide the velocity by the time taken
2. 9.375m/s
Same solution as before
