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asambeis [7]
3 years ago
6

In which block of the periodic table is uradium (U) found?

Physics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer: fBlock

Explanation:

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When an object has a net force of zero, then it is said to be in what?
Ganezh [65]

Answer: the object is said to be in a state of rest or uniform motion in a straight line

Explanation:Newton's first law of motion

3 0
3 years ago
If you measured all the energy related to motion and all the stored energy in the particles of a substance, which would you be m
Nady [450]

If you measured all the energy related to motion and all the stored energy in the particles of a substance, you would be measuring the thermal energy of the particles. If there is movement of the particles, they are also releasing energy in the form of heat.

3 0
3 years ago
A laser with a power of 1.0 mW has a beam radius of 1.0 mm. What is the peak value of the electric field in that beam
Fynjy0 [20]

Answer:

The peak value of the electric field is 489.64 V/m

Explanation:

Given;

power of the laser, P = 1.0 mW = 1 x 10⁻³ W

Radius of the beam, R = 1.0 mm = 1 x 10⁻³ m

Area of the beam = πr² = π(1 x 10⁻³ )² = 3.142 x 10⁻⁶ m²

The average intensity of the light = P / A

The average intensity of the light = ( 1 x 10⁻³) / (3.142 x 10⁻⁶)

The average intensity of the light = 318.27 W/m²

The peak value of the electric field is given by;

E_o = \sqrt{\frac{2I_{avg}}{c\epsilon_o}}\\\\E_o = \sqrt{\frac{2(318.27)}{(3*10^8)(8.85*10^{-12})}}\\\\E_o = 489.64 \ V/m

Therefore, the peak value of the electric field is 489.64 V/m.

4 0
3 years ago
A Capacitor is a circuit component that stores energy and can be charged when current flows through it. A current of 3A flows th
ddd [48]

Answer:

8\mu C

Explanation:

t = Time taken = 2\mu s

i = Current = 3 A

q(0) = Initial charge = 2\mu C

Charge is given by

q=\int_0^t idt+q(0)\\\Rightarrow q=\int_0^{2\mu s} 3dt+2\mu C\\\Rightarrow q=3(2\mu s-0)+2\mu C\\\Rightarrow q=6\mu C+2\mu C\\\Rightarrow q=8\mu C

The magnitude of the net electric charge of the capacitor is 8\mu C

4 0
3 years ago
Determine the index of refraction of glass that is struck by unpolarized light at 53.8 degrees and resulting in a fully polarize
nignag [31]

Answer:

The refractive index of glass, \mu_{g} = 1.367

Solution:

Brewster angle is the special case of incident angle that causes the reflected and refracted rays to be perpendicular to each other or that angle of incident which causes the complete polarization of the reflected ray.

To determine the refractive index of glass:

tan\theta_{P} = \frac{\mu_{g}}{\mu_{a}}                 (1)

where

\mu_{a} = refractive index of glass

\mu_{g} = refractive index of glass

Now, using eqn (1)

tan{53.8^{\circ}} = \frac{\mu_{g}}{1}

\mu_{g} = tan53.8^{\circ}

\mu_{g} = 1.367

5 0
3 years ago
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