Plzzzz help asap!!! marking brainiest!!!

Mathematics

1 answer:

Rama09 [41]3 years ago

3 0

Answer:

see below

Step-by-step explanation:

3 ^ ( 6/5)

The base a is 3

The power is 6 which is b

the root is 5 which is c

$\sqrt[5]{3^6}$

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If u, v, and w are nonzero vectors in r 2 , is w a linear combination of u and v?

Tju [1.3M]

Not necessarily. $\mathbf u$ and $\mathbf v$ may be linearly dependent, so that their span forms a subspace of $\mathbb R^2$ that does not contain every vector in $\mathbb R^2$ .

For example, we could have $\mathbf u=(0,1)$ and $\mathbf v=(0,-1)$ . Any vector $\mathbf w$ of the form $(r,0)$ , where $r\neq0$ , is impossible to obtain as a linear combination of these $\mathbf u$ and $\mathbf v$ , since

$c_1\mathbf u+c_2\mathbf v=(0,c_1)+(0,-c_2)=(0,c_1-c_2)\neq(r,0)$

unless $r=0$ and $c_1=c_2$ .

8 0

3 years ago

Among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a ma

scoundrel [369]

Answer:

Step-by-step explanation:

Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.

From the above we find that

a) either economics of Math course is

$315+213-123 =405$