All categories

3 years ago

Three Friends all have ages that are consecutive integers. The sum of their ages is 48. What is the age of the oldest friend?

Mathematics

2 answers:

zlopas [31]3 years ago

3 0

The oldest friend is 17 years old. 15+16+17. 5+6=11+7=18. 18+10+10+10= 48. get my level B) jk

Ksenya-84 [330]3 years ago

3 0

"The sum of their ages is 48" means x + (x + 1) + (x + 2) = 48

x + x + 1 + x + 2 = 48 

x + x + x + 1 + 2 = 48 

3x + 3 = 48 

3x = 48 - 3 

3x = 45 

x = 45/3 = 15 

So if the youngest is 15 (x = 15), then the oldest is x + 2 or 15 + 2 = 17

You might be interested in

It costs $0.60 to run a fan for 4 hours. How much does it cost to run the fan for 6 hours?

spin [16.1K]

Answer:

0.90$

Step-by-step explanation:

4hour=0.60

6hour=x

x=(0.60×6)/4

x=0.90$

5 0

3 years ago

Any help would be nice

mrs_skeptik [129]

Answer:

I think it's C.

Step-by-step explanation:

A. and D. don't make any sense so I assume they're incorrect. B. just seems wrong also by a small margin.

7 0

3 years ago

What is the value of the function y 2x – 3 when x = -5? A -5 B -1 C 2 D 3

aleksklad [387]

Answer:

The answer is -1 (B)

5 0

3 years ago

Read 2 more answers

Prove the theorem (AB )^T= B^T. A^T

Lisa [10]

Answer:

$(AB)^T = B^T.A^T (Proved)$

Step-by-step explanation:

Given (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

$(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\ = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T} \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)$

3 0

3 years ago

Help me out with this question (geometry)

nadezda [96]

Answer:

116

Step-by-step explanation:

13x-1 = 2(6x+4)

13x-1 = 12x+8

x=9

6 0

3 years ago