HL (hypotenuse leg)
Hope this helps
Answer:a.100+(hx25)
b.120+(hx20)
c.4 hours
h=hours
Step-by-step explanation:
Answer:
Not sure if this is correct but this is what I found.
area of sector=74.84
radius = 8
angle of sector=?
74.84=1/2×8²×angle of sector
74.84=32 × angle of sector
74.84/32= angle of sector
2.33875=angle of sector
Step-by-step explanation:
Sorry if it is incorrect.
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
