Answer:
The distance is:
Step-by-step explanation:
We re-write the equation of the line in the format:
Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.
In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:
Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:
We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:
Then we solve that equation for t, to get:
Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:
Then to find the distance we just use the distance formula:
So we get:
Answer:
30
Step-by-step explanation:
To find the determinant of a 3x3 matrix, you can use this method. (See picture.)
Start with the first number in the top row, and block off the row and column. A 2x2 matrix will be left. Find the determinant of this 2x2 matrix, and multiply it by the number in the top row.
Repeat for the other two numbers in the top row. Add the first result, subtract the second, and add the third.
det A = -2 [(3)(-5) − (a)(0)] − 2 [(0)(-5) − (a)(0)] + b [(0)(0) − (3)(0)]
det A = -2 (3)(-5) − 0 + 0
det A = 30
Answer:
p(x) is reflected over the x axis and is shrunken vertically by a factor of 2/3.
Step-by-step explanation:
Hope this helps.
The 1st one
Well it's the same as normal exponents so you multiply 2/3 x 2/3 x 2/3 x 2/3 x 2/3