Sample size, n = 75
Point estimate, p = 52/75 = 0.693
Z at 99.7% confidence interval ≈ 2.96
Population mean interval = p+/- Z*Sqrt [p(1-p)/n]
Substituting;
Population mean interval = 0.693 +/- 2.96*Sqrt [0.693(1-0.693)/75] = 0.693+/-0.158 = (0.535,0.851) or (53.5%,85.1%)
Answer:
3,400,000
Step-by-step explanation:
refer to attached for reference
in our case, the digit in the hundred thousands place is the number 4.
How we round this digit depends on the digit directly to the right of it (i.e the ten-thousands place).
If the digit to the right is less than 5, then leave the digit in the hundred thousands place the same and make everything else to the right zeros.
if the digit to the right is 5 or greater, then increase the digit in the hundred thousands place by 1 and then make everything else to the right zeros.
in our case, the digit to the right of the hundred thousands place is the number 2, this is less than 5, so we leave 4 the same and make everything esle to the right zero.
i.e. 3,400,000
Answer:
0.35 is the mean of the sampling distribution of the proportion.
Step-by-step explanation:
We are given the following in the question:
Percentage of voters who voted for recall = 35%

Sample size, n = 3150
We have to find the mean of the sampling distribution.
Formula for mean of sampling distribution:

Putting values, we get,

Thus, 0.35 is the mean of the sampling distribution of people sampled in an exit poll who voted for the recall.
180 is the answer. Hope you get it right! (:
The answer is (-4,-4) because y has to equal x, the first -4 is the x and the second one is the y