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Tatiana [17]
3 years ago
6

Help please!! On 19 and 20!!! There are only 2 answers in each!

Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0
For 19 the first and second expressions and for 20 the first and second as well
Ghella [55]3 years ago
6 0
19. 2(5x+4)+x+2 would work

20. Would probs have to be 18x+12y
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Find the constant of variation for the relationship f(x)= 30x.
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For a direct variation, f(x) = kx. Therefore, for f(x) = 30x, constant of variation (k) = 30.
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Eve paid $1.12 for dozen eggs at store. determine cost of 3 eggs.
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he would have paid 3.36

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A circle has a circumference of 9π what is the diameter?
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C=πd  where C=circumference, π=the constant pi, and d=diamter

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3 years ago
Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

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4 years ago
How do you <br> Write <br> 29/9<br> as a mixed number.
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<em>3 x 9 = 27</em>
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<u>Mixed number: 3 2/9</u>
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