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drek231 [11]
2 years ago
5

It takes Caroline 1/5 of an hour to walk a mile. Four of Caroline's friends time themselves on their own walk of different lengt

hs. Which friend is walking at the same rate as Caroline? *
Mathematics
1 answer:
Basile [38]2 years ago
5 0

Answer:

Jeanette is the friend walking at the same rate as Caroline. This is because Jeanette also takes 1/5 of an hour to walk a mile.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

It takes Caroline 1/5 of an hour to walk a mile. Four of Caroline's friends time themselves on their own walk of different lengths. Which friend is walking at the same rate as Caroline? If:

David walked 1/2 a mile in 2/5 an hour

Jeanette walked 1/2 a mile in a 1/10 an hour

Kay walked 1/5 a mile 1/2 a hour

Mark walked 1/3 a mile in 3/5 an hour

The explanation of the answer is now given as follows:

To determine which friend is walking at the same rate as Caroline, we first convert their rate to number hours it takes to walk a mile as follows:

a. David walked 1/2 a mile in 2/5 an hour

This implies that:

(1 / 2) * 2 = 2/2 = 1 mile

(2 / 5) * 2 = 4/5 of an hour

Therefore, David takes 4/5 of an hour to walk a mile.

b. Jeanette walked 1/2 a mile in a 1/10 an hour

This implies that:

(1 / 2) * 2 = 2/2 = 1 mile

(1 / 10) * 2 = 2 / 10 = 1/5 of an hour

Therefore, Jeanette takes 1/5 of an hour to walk a mile.

c. Kay walked 1/5 a mile 1/2 a hour

This implies that:

(1 / 5) * 5 = 5/5 = 1 mile

(1 / 2) * 5 = 5 / 2 = 2.5 hours

Therefore, Kay takes 2.5 hours to walk a mile.

d. Mark walked 1/3 a mile in 3/5 an hour

This implies that:

(1 / 3) * 3 = 3/3 = 1 mile

(3 / 5) * 3 = (3 * 3) / 5 = 9 / 5 = 1.8 hours

Therefore, Kay takes 1.8 hours to walk a mile.

Conclusion.

Based on the calculations above, only Jeanette is walking at the same rate as Caroline. This is because Jeanette also takes 1/5 of an hour to walk a mile.

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