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3 years ago

One purpose of General T.Sherman's march to the sea was to

Mathematics

1 answer:

Murrr4er [49]3 years ago

7 0

Answer:

Step-by-step explanation: He slashed across the South destroying farms and land in a scorched Earth tactic, which was really damaging to the South because the land they had was all they had.

It's not B because they didn't need rest, he wasn't sailing North so it's not C, and he didn't have anything to prove himself as a skilled general, he already was a skilled general.

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Pump 1 can empty a pool in 8 hours while Pump 2 can empty the same pool in 9 hours. If the two pumps worked together, how long w

yan [13]

Rate of pump A: 1/8 of a pool per hour
Rate of pump B: 1/9 of a pool per hour
Combined rate: 1/8+1/9 = 17/72 +1/9 = 25/72

So if they work together, the two pumps have a combined rate of 25/72 of a pool per hour (i.e in one hour, the two pumps will empty 25/72 of the pool)

But we want to empty ONE pool (not 25/72 of one). So we need to multiply 25/72 by some number x to get 1.

Now solve for x
x=2.88
It will take the two pumps 2.88 hours to empty the pool.
2 hours 52 minutes 50 seconds

7 0

3 years ago

The distance d of a particle moving in a straight line is given by d(t) = 2t^3 + 5t – 2, where t is given in seconds and d is me

Amanda [17]

Answer: 299 m/s

Step-by-step explanation:

The first step is to take the first derivative of the equation given. This will give us the equation for velocity which we will then substitute the 7 in for t.

To derive the equation you multiply the coefficient by the power of the variable, then subtract one from the variable.

v(t) = 6t^2 + 5

Now input 7 in for t to find the velocity.

v(7) = 6(7)^2 + 5

v(7) = 299 m/s

6 0

3 years ago

On a trip to Griffith Observatory, Dave rode his bicycle six more than twice as many miles in the afternoon as in the morning. I

podryga [215]

Answer:

Dave rode his bicycle 17 miles in the morning

Dave rode his bicycle 40 miles in the afternoon

Step-by-step explanation:

* Lets study the information to solve the question

- Dave rod his bicycle in the morning and again in the afternoon

- Six more than twice as many miles in the afternoon as in the morning

means the distance in the afternoon is 6 more than twice the distance

in the morning

- The entire trip was 57 miles means the total distance in the morning

and in the afternoon was 75

* To solve the question let the distance in the morning is x miles

∵ The distance in the morning = x miles

∵ The distance in the afternoon is 6 more than twice the distance

in the morning

∴ The distance in the afternoon = 2x + 6 miles

∵ The distance in entire trip = 57 miles

- The distance in the morning and the distance in the afternoon = 57 miles

∴ x + (2x + 6) = 57 ⇒ simplify

∴ 3x + 6 = 57 ⇒ subtract 6 from both sides

∴ 3x = 51 ⇒ divide both sides by 3

∴ x = 17 miles

∵ The distance in the morning is x miles

∴ Dave rode his bicycle 17 miles in the morning

∵ The distance in the afternoon = 2x + 6 miles

- Substitute the value of x

∴ The distance in the afternoon = 2(17) + 6 = 34 + 6 = 40 miles

∴ Dave rode his bicycle 40 miles in the afternoon

4 0

3 years ago

Devaughn is 9 years younger than Sydney. The sum of their ages is 61. What is Sydney's age?

Lelu [443]

52? ahh thats what im thinking. Maybe wait for someone elses answer

6 0

3 years ago

Read 2 more answers

Twenty-seven is % of 60 help mee asap

jok3333 [9.3K]

Answer: The answer is: " 45 % " .

________________________________________________

→ " Twenty-seven is 45 % of 60. "

________________________________________________

Step-by-step explanation:

________________________________________________

The question asks:

" 27 is what % {percentage] of 60 " ? ;

________________________

So: " 27 = (n/100) * 60 " ; Solve for "n" ;

________________________________________________

Method 1:

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→ (n/100) * 60 = 27 ;

Divide each side by 60 :

→ [ (n/100) * 60 ] / 60 = 27 /60 ;

to get:

→ (n/100) = 27/60 ;

Now: Cross-factor multiply:

→ 60n = (27)*(100) ;

to get:

→ 60n = 2700 ;

Divide each side by "60" ;

→ 60n = 2700/ 60 ;

to get: n = 45 ;

________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2:

________________________________________________

The question asks:

" 27 is what % {percentage] of 60 " ?

________________________

To solve this problem:

Rephrase this question as:

________________________

" 27 is 60% of what number ? "

→ The answer will be the same!

________________________

→ 27 = (60/100)* n ; Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→ 100 * 27 = 100 * [ (60/100)* n ] ;

to get:

→ 2700 = 60n ;

↔ 60n = 2700 ;

Divide Each Side of the equation by "60" ;

→ 60n/60 = 2700 / 60 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2: Variant 1 of 2:

________________________________________________

When we have:

→ 27 = (60/100)* n ; Solve for "n" ;

________________________

Note that: "(60/100) = (60÷ 100) = (6 ÷ 10)" ; since: in "(60/100)" ; the "zero" from the "numerator" cancels out; And: the "last zero" in "100" — from the "denominator" cancels out; since we are dividing "each side" of the fraction by "10" ;

→ "(60÷10) / (600÷10)" = " 6/10 " ;

→ " (6/10)" ; that is; "six-tenths"} ;

→ can be represented by: " 0.6 " ;

→ {by convention; but specifically, here is the explanation} — as follows:

________________________

→ "(6/10)" = " (6 ÷ 10) " ;

Note: When dividing a number by "10" ; we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".

Note: When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10". We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying; and to the left if we are dividing. In this case, we are dividing "6" by "10 " :

→ " 6 ÷ 10 = ? " ;

→ " 6. ÷ 10 = ? " ;

We take the: " 6. " ; and move the decimal point "one space backward [i.e. "to the left"]; since we are dividing by "10" ;

→ to get: " .6 " ; & we rewrite this value as "0.6" in a rewritten equation:

________________________

So; we take our equation:

→ 27 = (60/100)*n ; And rewrite—substituting "0.6" for

"(60/100)"— as follows:

________________________

→ 27 = (0.6)n ; ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

→ 10 * [ (0.6)n ] = 27 * 10 ;

to get:

→ 6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 6n / 6 = 270 / 6 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2 (variant 2 of 2):

________________________________________________

We have the equation: 27 = (60/100)* n ; Solve for "n" ;

________________________

Note: From Method 2 (variant) 1 of 2— see above):

________________________

Note: Refer to the point at which we have:

________________________

→ " { (60÷10) / (600÷10)" = " (6/10) " ; that is; "six-tenths"} ;

________________________

Note that the fraction— "(6/10)" ; can be further simplified:

→ "(6/10)" = "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ; with: "(3/5)" :

→ 27 = (3/5)* n ; Solve for "n" ;

↔ (3/5)* n = 27 ;

↔ (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→ 5* (3n/5) = 27 * 5 ;

to get:

→ 3n = 135 ;

Divide Each side of the equation by "3" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 3n / 3 = 135 / 3 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Hope this answer is helpful!

Wishing you the best in your academic endeavors

— and within the "Brainly" community!

________________________________________________

7 0

3 years ago

Read 2 more answers