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exis [7]
3 years ago
7

I’m really confused on how to solve this can someone please help me fast!!!!

Mathematics
2 answers:
Rasek [7]3 years ago
7 0

Answer:

105.12

Step-by-step explanation:

area of rectangle = 10 x 8 = 80

area of semi circle = 3.14 x 4^2     (4 because the diameter is 8 so half of it)

= 50.24

50.24 / 2 = 25.12 (as it is a semi-circle)

80 + 25.12 = 105.12

beks73 [17]3 years ago
6 0

Answer:

130.24

Step-by-step explanation:

8*10+3.14*4^2=

80+50.24=130.24 ft^2

Cut the shape into a semi-circle and rectangle (with length 10 and width 8).

You'll find the radius of the semi-circle is 4.

The area of the rectangle is 80.

Then use the pir^2 formula but replace pi with 3.14

3.14 multiplied by radius 4 squared is 50.24

50.24 plus 80 is 130.24 ft squared.

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The cost C (in dollars) to participate in a ski club is given by the literal equation C=85x+60, where X=C/85-12/17 is the number
dybincka [34]

Given:

The cost C (in dollars) to participate in a ski club is given by,

\begin{gathered} C=85x+60 \\ (or) \\ x=\frac{C}{85}-\frac{12}{17} \end{gathered}

Where x is the number of ski trips we take.

To find:

The number of ski trips when a total cost of $315 and $485 is spent.

Explanation:

Substituting C = 315 in the given equation we get,

\begin{gathered} x=\frac{315}{85}-\frac{12}{17} \\ x=\frac{315-60}{85} \\ x=\frac{255}{85} \\ x=3\text{ ski trips} \end{gathered}

Substituting C = 485 in the given equation we get,

\begin{gathered} x=\frac{485}{85}-\frac{12}{17} \\ x=\frac{485-60}{85} \\ x=\frac{425}{85} \\ x=5\text{ ski trips} \end{gathered}

Thus,

If we spend a total cost of $315, we can take 3 ski trips.

If we spend a total cost of $485, we can take 5 ski trips.

Final answer:

• If we spend a total cost of $315, we can take 3 ski trips.

,

• If we spend a total cost of $485, we can take 5 ski trips.

8 0
11 months ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
Simplify 4sqrt6/sqrt30 by rationalizing the denominator
andreev551 [17]
4sqrt5/5

see the attachment

8 0
3 years ago
What is 5/6mn-7/8mn? Explain how you got it
Misha Larkins [42]
-1/24 is that true?????????
8 0
3 years ago
Can I get some help on 2,4,20,40, and 50 please
scoundrel [369]

Answer:

2. power

4. tenth

20. hundred-thousandth

40. 5.063

50. 67/10

Step-by-step explanation:

20. If the underlined digit is the zero, the answer is "hundred-thousandth." It's hard to tell from the picture if zero is the underlined digit.

40. 5 and 63/1000 = 5 + 63/1000 = 5 + 0.063 = 5.063

50. 6.700 = 6700/1000 = 67/10

5 0
3 years ago
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