Alright, lets get started.
Please refer the diagram I have attached.
The angle between Melville Road and Emerson Avenue is 119°.
Hawthorne Lane bisects the angle formed by Melville Road and Emerson Avenue.
So, angle between Hawthorne Lane and Emerson Avenue will be = 
°
Now, angle between Emerson Avenue and Thoreau Street is 135°.
Dickinson Drive bisects the angle formed by Emerson Avenue and Thoreau Street.
So, angle between Dickinson Drive and Emerson Avenue will be = 
°
So, the complete angle between Hawthorne Lane and Dickinson Drive will be = 
°
So, the answer is 127 °. : Answer
Hope it will help :)
BTW,
KEY:
• exponents are going to be written as “^(x)”.
• if I put “huh” or “nope” or “what” (etc.) that means I don’t know how to solve it.
1. 49a
2.-15x^(2)+2y^(2)
3.-23a+2b+6
4. 0
5.-9c+3d
6. 4a+14b+c
7.-6a+2b+62
8.-3x+8
9. 16x^(2)-y+x+z
10.-6x
11.-8xy+2
12.-15a+3b
13. nah bruh
14. nope
15. 1.5a
16. -10a-2205
17. -4cd+55
18.-4x+2y+3
19. -67,209
20. huh?
21. what??
22. 18a+4b
23. 8y+3x+6
24.-2x+2y+6r+2
25. 4a^(2)+2a+2b+3
Answer:
1.60 
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area = 
So that,
for the inner part of the pipe,
r = 
= 
= 2.5 feet
Area of the inner part of the pipe =
= 3.14 x 
= 19.625
Are of the inner part of the pipe is 19.63 .
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r = 
= 2.6 feet
Area of the pipe =
= 3.14 x 
= 21.2264
Area of the pipe is 21.23 .
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60 .
Answer: 0.44..repeating (meaning it goes on forever)
Step-by-step explanation:
1. go on google
2. type in 4/9
3. click the enter button
4. you got your answer
5. ur WeLcOmE
(5x6+2x3)/(3x2x3)= answer is 2
