Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
Answer: x=4
Step-by-step explanation: first you should write it out like it is telling you. put a line and EG is the line and f is in the middle of the two looks kinda like this E F G but they are on a line EG= 25 that means the whole thing equals 25. EF= 2x-6 and FG= 4x+7. when you plug that in it should look like this 25=2x-6+4x+7 then solve.
Answer:
6/8
Step-by-step explanation:
I answered this math question on edge and 100%.
See the attachment below.
Hope it helps!
Answer:
Step-by-step explanation:
<u>The rule of 90° counterclockwise rotation about the origin:</u>
<u>Apply the rule to the point T:</u>